put six on each side first5.39.217.77:88984 v8 o# X+ a2 |
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from the heavier six, split it to three on each side
1 [4 A2 g- L G. ]7 G4 [ S% r5.39.217.77:8898
H$ l& F, {0 h/ }, E9 h% Tthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |