put six on each side first5.39.217.77:8898" q) _3 s2 `: H4 E% ~; k
( v$ S# T6 `7 lfrom the heavier six, split it to three on each sidetvb now,tvbnow,bttvb- v% W! m0 J& T7 D
9 q. _* C& B9 p
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |