put six on each side firsttvb now,tvbnow,bttvb0 f/ D* }; D% C9 Z7 ]
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from the heavier six, split it to three on each side
. c" X4 A* P# N, N/ `! D0 E5.39.217.77:8898; U8 ]/ |4 L1 K7 c
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |