let the 12 balls be numbered 1,2,3,4,5,...,12
* h2 |/ s4 C5 A' Qweight 1234 with 56785.39.217.77:8898. x* [7 C' f3 w* ?, r
case 1) j3 ?; P5 \/ j2 H
if 1234>5678, then weight 125 with 678
" v, C/ N* A* a7 _0 S4 t! @) s9 C5.39.217.77:8898if 125>678, then weight 1 with 2
, U! O" H4 v- s$ gtvb now,tvbnow,bttvbif 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2+ _' \+ B7 O7 u M3 Q
if 125=678, then weight 3 with 9tvb now,tvbnow,bttvb, G3 H3 ]! T+ l
if 3=9 it is 4, else it is 3
( @0 \% a* a: |* H' S' v7 Mtvb now,tvbnow,bttvbif 125<678, then ewight 3 with 4
S$ I; z9 M& o" tif 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4tvb now,tvbnow,bttvb5 U5 m8 Z; L1 _1 L0 a, A% V# ?, Z
4 {0 s; {' F5 a2 U2 H8 b1 E
case 2
! Q$ \: Y& ?$ ~& h# ^2 p' q }repeat above for 5678 instead of 1234 if 1234<5678
/ @5 U d3 v$ B5.39.217.77:8898公仔箱論壇+ {; Q9 U& O! T6 i! y$ x9 C
case 3! [' [- A% `# ?& c- n' y
1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain! V. P# `- u) k5 E6 h( |$ G; e
4 m9 R3 ]( K$ H7 N$ B1 G3 l
[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ] |
發表於 2007-5-7 11:25 AM
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太简单了吧？