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好難呀...
難...
好難呀....
ddd
好難喎
There is 12 balls.. divide them into piles of 4tvb now,tvbnow,bttvb; C6 g) i; |" f' Y2 G6 m4 X, G1 ^% U
so 3 groups for 4..name is A,B,C5.39.217.77:8898! v: m) u( r8 q" T  H: q2 M4 S
case 1:
" d' j* ?, e3 _+ N' M; ]3 w6 Dtvb now,tvbnow,bttvbmeasure A -- B 公仔箱論壇- G3 ]5 R$ K% l
A or B is heavier 公仔箱論壇# c# _/ y1 w0 U" `9 q2 I( K' ~/ {( z0 ~
divide that group into 2 by 2
- J- f5 ?. y2 U4 I0 [  X% l6 }then divide heavier group into 1 by 1
- M% ]3 q1 |( f  j& m2 X2 |1 O& e5.39.217.77:8898$ e4 e! @, w2 b8 J' s5 j5 L  V
case 2:
2 ?( }. c0 ]; c$ U4 U公仔箱論壇A and B is the same.. therefore C has the heavier balltvb now,tvbnow,bttvb; R& ~& s9 U3 I/ t( r+ Z/ w
divide C into 2 by 2tvb now,tvbnow,bttvb& |$ @) o$ i- c5 [/ X0 T( X
then divide heavier group into 1 by 1..5.39.217.77:88986 T9 ^1 V6 V1 E" |  X  E. y' [

- G3 _6 ~# B6 X( N/ R6 Y+ Atvb now,tvbnow,bttvbgot it in 30 seconds.. not so hard -.-'
thx
i got it.... separate into 4 group 3(a)3(b)3(c)3(d), weight 2 of them(a,b), if it is the same, weigh b and c, if they are the same too... then the different ball must be in group d. if you weight different, you identify that group according to the different group. Also, we know the the different ball is heavier or lighter.tvb now,tvbnow,bttvb' v/ c1 L3 E* R7 E9 U3 c8 W- |% Y
5.39.217.77:8898% @% m$ e& o/ V( R5 c+ e' O
they separate into 3 group111, weight 2 of them. if they are the same, the extra ball will be the different ball. if they are different, the heavier/ lighter ball will be the different one according to the previous weight.
睇下先
do this is so boring...
9 |' U, C) n. _5 J4 i. R. _play game la~~~
[-X OK la^:)^ ^:)^
一知道有答案睇就唔想谂咁耐了
?
why?
多謝大大的分享
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