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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。7 k# P$ l9 K$ ?1 m6 P
共四堆
9 _" h+ L/ D8 l3 utvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重
0 j  D' `' z8 a- Y* m# r; E6 vtvb now,tvbnow,bttvb在异常的那一堆中在称一次tvb now,tvbnow,bttvb2 f' l, y' p$ z
就可以找到了
divde the 12 balls into 3 sets of 4. & ~% p( W- f1 j( H
weight any 2 sets.
5 p. I' D. r% _0 {TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if the 2 sets are equal, then you know the heavy one is in the third  F+ b& K% y: d' u& T
if one of the 2 is heavier, then the heavy one is in that set; G% D8 C& u4 P$ c8 @5 e' f
then divide the 4 balls into 2.
* W8 W1 u5 p* E4 O3 {$ W8 ztvb now,tvbnow,bttvbweigh them
4 ?5 K- V8 K4 U9 r4 ]% T' e5.39.217.77:8898and divide the heavier into 1
) C% B* F' h% n公仔箱論壇and weight them.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2 u+ p2 ~9 ~# `  s  O
3 x weighing and get the ans.  
$ V: _. H* r+ T& j7 `in less than 15 secs.
1. 6 aside and weight.
. z& ~% w; W' x/ z2. heavier side from (1), 3 aside weight again.7 X+ k& r1 U+ q% D1 H
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
" }# c5 S2 K% g" I5.39.217.77:8898" X5 T2 T9 v: j0 s; b7 c0 U
but i have a question. 重量異常 can be heavier or lighter.... so......
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