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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
0 H  f$ U4 j2 `8 d5.39.217.77:8898共四堆
( ^1 Y. ~1 t- r+ ]) n& N3 c9 O称两次得出异常的在那一堆,其轻重
/ c0 `$ x- L. V1 ?5 m& V. f2 U在异常的那一堆中在称一次5.39.217.77:88980 x0 T3 V) U, F0 B% @7 U
就可以找到了
divde the 12 balls into 3 sets of 4.
& {. M1 r5 C- _weight any 2 sets.
6 L/ C! k, X! }tvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third
' V9 b/ R# j) uif one of the 2 is heavier, then the heavy one is in that set
' g( X: y1 K6 H& ?  Ntvb now,tvbnow,bttvbthen divide the 4 balls into 2.5.39.217.77:88983 j8 ]0 m+ {  y9 i- U& T, W# d
weigh them
2 B8 v3 ^( P& Z& Wand divide the heavier into 1
& v  P- ]8 r) C; B( h4 D( `3 Wand weight them.
: Q, c* ?; A' R! b/ P! h& d5.39.217.77:88983 x weighing and get the ans.  tvb now,tvbnow,bttvb: I9 A* B; r5 `6 X* l
in less than 15 secs.
1. 6 aside and weight.
  q0 U. y4 D$ _+ m5 M9 a, ]2. heavier side from (1), 3 aside weight again.  u) X2 _+ v& P8 L5 O' a  V
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 公仔箱論壇! F  x7 t- w$ O/ u

4 |( Q+ X6 l8 f4 jbut i have a question. 重量異常 can be heavier or lighter.... so......
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