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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。* }7 ~* u% q- m  L' {, f
共四堆1 U/ T5 X; M0 F* k  a! I: ~
称两次得出异常的在那一堆,其轻重公仔箱論壇* X! [. R4 o6 N5 J
在异常的那一堆中在称一次公仔箱論壇  X& t' @, B) C4 _9 {. r
就可以找到了
divde the 12 balls into 3 sets of 4. 1 J, Q' T/ d- \& |
weight any 2 sets.
3 q1 M4 P$ R( l0 n3 p7 gtvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third: x+ h! n% E& k
if one of the 2 is heavier, then the heavy one is in that setTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。  D3 @6 R3 b" N5 |' k. Q2 \7 z
then divide the 4 balls into 2., g2 j  g( a! h3 F1 C- [, g$ Y
weigh them
1 E8 A' s( `1 R公仔箱論壇and divide the heavier into 1
/ K' p5 Y" o* P5.39.217.77:8898and weight them., g* h5 S0 ~' }8 S; g
3 x weighing and get the ans.  
/ T& e7 @" e$ t2 t* @& F# U2 {公仔箱論壇in less than 15 secs.
1. 6 aside and weight.( R! \( ~  g8 R, ^, @
2. heavier side from (1), 3 aside weight again.
0 }2 y$ G, e$ w+ d/ u! I; F3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
: J% B# N7 S, e, V$ n6 w" E
+ M+ y! L  d) \( |- m公仔箱論壇but i have a question. 重量異常 can be heavier or lighter.... so......
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