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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆2 L; z% c% p4 I* p0 y
共四堆公仔箱論壇, L* a* D0 O2 B# H
称两次得出异常的在那一堆,其轻重9 A5 x+ I9 C! G# T" v
在异常的那一堆中在称一次
4 t8 c9 J3 Q2 q/ T8 K. F就可以找到了
divde the 12 balls into 3 sets of 4. 5.39.217.77:88983 O* S2 ]2 q! ]+ h, Z7 J0 Z
weight any 2 sets.
) n% R5 S1 W3 L9 j& u: m; X; d公仔箱論壇if the 2 sets are equal, then you know the heavy one is in the third5.39.217.77:88988 i! R8 T7 v3 b% T
if one of the 2 is heavier, then the heavy one is in that setTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 c1 G9 Q4 d2 H+ d
then divide the 4 balls into 2.$ N( n6 J& g: F! Y. W
weigh themtvb now,tvbnow,bttvb) V/ u( _/ w+ B% X
and divide the heavier into 15.39.217.77:8898  V  [1 K; {# p! t( A4 c
and weight them.
/ J) T' a8 O% M0 ?' T9 ^3 x weighing and get the ans.  公仔箱論壇( _: W3 t  ?. u, Y: P4 U! I
in less than 15 secs.
1. 6 aside and weight.
/ D$ S4 v! n+ ^' l$ z) ]tvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.
  {) l" _# F' Q3 b5.39.217.77:88983. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.77:8898; P# C3 I5 {) e% [6 ~4 t& M5 H7 Y

# }7 K  ]! M, L/ Y# gTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。but i have a question. 重量異常 can be heavier or lighter.... so......
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