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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb. m3 y: u! \! Y- \5 F
共四堆TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。* C' j% G1 L! L1 ^: }" b8 M. s
称两次得出异常的在那一堆,其轻重
/ S; e& m4 W" A# e- d5 m在异常的那一堆中在称一次
$ v; R0 Z- `; }0 A0 Utvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" c0 e, l; _4 w7 R4 Z3 K
weight any 2 sets.
/ r% }- k$ i5 ~9 c# ^) @if the 2 sets are equal, then you know the heavy one is in the third7 h4 `) C& t; u5 R; s5 B9 U4 k
if one of the 2 is heavier, then the heavy one is in that set5.39.217.77:88982 B4 u  x0 j" N' G6 P# d
then divide the 4 balls into 2.4 x  p% ~: _% [: R
weigh themtvb now,tvbnow,bttvb! ~! b' m8 F( k% R! m( _
and divide the heavier into 1公仔箱論壇  \5 p2 m* `, |# Y. ^( g2 z6 c. y* ^9 M  n
and weight them.
) I) v) Q3 W+ B6 t7 @) j5.39.217.77:88983 x weighing and get the ans.  
! x  i7 D; E( f  E7 e* a公仔箱論壇in less than 15 secs.
1. 6 aside and weight.. R8 C% q& g9 H
2. heavier side from (1), 3 aside weight again.tvb now,tvbnow,bttvb5 x$ t5 i9 l) ]
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
9 f/ U. Y1 g9 v9 v' j5.39.217.77:8898
7 q1 q0 a7 J6 S' j1 m$ M/ Itvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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