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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
; l. u- f$ s. j4 e+ K6 C0 A共四堆8 W2 x* q+ J* G6 h& J
称两次得出异常的在那一堆,其轻重
4 v' M. M, v8 w9 v( M7 W/ v  K公仔箱論壇在异常的那一堆中在称一次
' H8 e. q, C! Z3 q就可以找到了
divde the 12 balls into 3 sets of 4. 5.39.217.77:8898: r8 Q& ~8 W  U. J
weight any 2 sets.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% P1 ~" y! }$ n8 \
if the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇* Z# ~. \8 X0 o" B4 d; w
if one of the 2 is heavier, then the heavy one is in that setTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。; S/ H2 k& R0 }  s
then divide the 4 balls into 2.
" f# }1 |) Q( Fweigh them
! L  h! U8 m' s7 aand divide the heavier into 1
% r+ O+ }1 g' s7 n2 |, \9 v  s0 X5.39.217.77:8898and weight them.5 L2 x4 L: r4 J) J- m4 {9 d
3 x weighing and get the ans.  tvb now,tvbnow,bttvb7 t$ F' C; w: _. `2 g3 f. n# I
in less than 15 secs.
1. 6 aside and weight.
' f) d% p" n1 Z9 a2. heavier side from (1), 3 aside weight again.
. Q0 N1 E# N) Z% d) {3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. * _; D; M* w7 s1 d9 r

7 @; V( [6 Z) F" j; F0 Nbut i have a question. 重量異常 can be heavier or lighter.... so......
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