lux1261

答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1

lesley

^:)^ >:D<

leekh

thx

jc49

let cc

Special_Forces

not possible

sm911118

不知道要怎麼做阿??

laou

hao

jen198053

there got more simple way to do it, just read my way, the one i answered before

samkk123

the

hakis

see 了

jenfien

第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了

fxenon

how?

nyb

先分3个一堆
# v- ~+ @) c3 I  C共四堆  o4 H/ M; E1 C- x
称两次得出异常的在那一堆，其轻重
5 q2 T3 ]2 Q; \5.39.217.77:8898在异常的那一堆中在称一次公仔箱論壇4 E+ N: o8 m2 D7 @4 s1 Z
就可以找到了

ceteriz

divde the 12 balls into 3 sets of 4.
' a) j1 q9 @/ X) l+ R0 w) Otvb now,tvbnow,bttvbweight any 2 sets.
7 @9 x+ @  p4 c" g* Ftvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third* e) @; x3 ?) S0 B' G2 s0 _
if one of the 2 is heavier, then the heavy one is in that set
# ~. f  W& U* I$ o0 I* W公仔箱論壇then divide the 4 balls into 2./ Y# v5 V0 r& a7 D. ]
weigh them5.39.217.77:88987 c2 B2 c5 m$ w; ?$ V
and divide the heavier into 1
8 ?! L/ T. [. u' V# s! Gand weight them.
* ]! y7 n2 M7 W2 M) g7 _( x6 E1 P* z) u5.39.217.77:88983 x weighing and get the ans.  $ _$ X0 y2 r; b5 Z" Y
in less than 15 secs.

kino_kino

1. 6 aside and weight.5.39.217.77:88983 V' v) t) x6 E5 f6 D
2. heavier side from (1), 3 aside weight again.
2 `7 \0 x& I+ j4 [( B, o8 C! m5.39.217.77:88983. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.77:8898. \3 k* k; X% s' u0 C& u
0 u# g% P5 U2 V. }
but i have a question. 重量異常 can be heavier or lighter.... so......