返回列表 回復 發帖
答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆! t# v5 D, Y! O) [9 {
共四堆
, ~: v7 I9 E! Z称两次得出异常的在那一堆,其轻重
$ }7 i- G+ h" @+ a在异常的那一堆中在称一次tvb now,tvbnow,bttvb$ a0 j% l4 D4 d) m
就可以找到了
divde the 12 balls into 3 sets of 4. 5.39.217.77:88980 }- Q, e; M: [- N4 b- k
weight any 2 sets.9 k8 J$ r: T2 S* i5 S
if the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇, G5 _2 ^# z8 y* l* W
if one of the 2 is heavier, then the heavy one is in that set
" S4 {2 l# i1 S3 i8 Othen divide the 4 balls into 2.
- p0 n/ A1 `! B3 |3 Xweigh them; v* w) m$ [: ~) z* a9 w- c* B6 Y
and divide the heavier into 1( I9 `; [" t. V. C' S
and weight them.
; j; ^+ L/ s% @) r5.39.217.77:88983 x weighing and get the ans.  
" G  s% y- e# b  s6 A3 R# o) P7 T0 n4 Fin less than 15 secs.
1. 6 aside and weight.
4 _# X9 G8 M* @: `公仔箱論壇2. heavier side from (1), 3 aside weight again.+ c0 ?% ~# R2 O8 z+ s- U
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
& K+ q% N- d( Q+ r3 K公仔箱論壇
; t/ J$ w8 E5 X3 x- w( v6 ttvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
返回列表