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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb5 G0 Y3 i5 X5 s, t7 E
共四堆tvb now,tvbnow,bttvb) s$ i( J5 u2 I9 P7 m
称两次得出异常的在那一堆,其轻重
1 ^5 h+ K' R& t5 z' Y5.39.217.77:8898在异常的那一堆中在称一次
# t8 m, G% H8 \* t3 ]1 L$ \3 E( ]% M% e就可以找到了
divde the 12 balls into 3 sets of 4.
& I1 a% [$ k( k$ W! pweight any 2 sets.公仔箱論壇+ a, Z# G8 g* f2 @( e8 A, P; |
if the 2 sets are equal, then you know the heavy one is in the third
, g& S$ O. @( j* Z+ d- E6 X公仔箱論壇if one of the 2 is heavier, then the heavy one is in that set
( e; Y2 y% d* G/ u/ U5 L5.39.217.77:8898then divide the 4 balls into 2.
  d" M# ~6 u3 `' t3 UTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weigh them
* K1 G2 U" U& ^( l5.39.217.77:8898and divide the heavier into 1
9 I3 K9 A& ^& n9 J2 atvb now,tvbnow,bttvband weight them.
4 }# V* v0 p( ktvb now,tvbnow,bttvb3 x weighing and get the ans.  
: l+ C8 S1 F+ C7 H' e! e1 F# b( CTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight.6 v/ K( X: @4 H9 ]3 S
2. heavier side from (1), 3 aside weight again.
5 p1 ]# U& C* k9 K+ K! x3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
2 |6 E) q' y0 M# c% g% ~# U. h5 I+ P公仔箱論壇公仔箱論壇% ]- w; u4 X/ R' Q2 g" K2 P' v
but i have a question. 重量異常 can be heavier or lighter.... so......
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