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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb) P/ y8 k& P% q
共四堆, Z& X. U9 h9 b9 T2 S% j% N* K
称两次得出异常的在那一堆,其轻重
/ s' C3 F" |! w& ?5 |, v5 O+ U  Y4 J在异常的那一堆中在称一次tvb now,tvbnow,bttvb1 A, m3 u- \8 r7 F
就可以找到了
divde the 12 balls into 3 sets of 4.
" F- z' J: n5 Y4 }! ^2 W+ uweight any 2 sets.公仔箱論壇3 m  D+ a1 E  y5 U* R% h  @
if the 2 sets are equal, then you know the heavy one is in the third
2 g% X+ E3 \- y( b2 d4 T" P" r: ~公仔箱論壇if one of the 2 is heavier, then the heavy one is in that set
1 d' z- u$ ?" u% g, l, J/ K; F( L8 ZTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。then divide the 4 balls into 2.; f& O; z# {) e' r$ R1 |8 t
weigh them
  i. I" d: x, F+ Z5.39.217.77:8898and divide the heavier into 1
( p, ^9 P# x9 S) Qand weight them.
' V* s: N$ k: O7 H. n, B6 V8 ^: S' q3 x weighing and get the ans.  
# S8 r0 Q2 R+ h" N公仔箱論壇in less than 15 secs.
1. 6 aside and weight.5.39.217.77:8898& M+ U& `$ ?* \0 l
2. heavier side from (1), 3 aside weight again.7 P+ K8 O' h/ f5 A
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.77:88989 [5 p; B5 J8 M) L& u! G
5.39.217.77:8898$ ^' W8 z0 F1 |$ V+ |/ q- ^
but i have a question. 重量異常 can be heavier or lighter.... so......
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