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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
, p7 T$ h5 |6 ?( G! wtvb now,tvbnow,bttvb共四堆TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。& I# I1 |( E- R% j. u2 E
称两次得出异常的在那一堆,其轻重5 _" H# Z4 s# b+ h0 k& M
在异常的那一堆中在称一次
9 A4 b& n1 K/ _* ^. ^* F; Q4 E0 Z" ^公仔箱論壇就可以找到了
divde the 12 balls into 3 sets of 4. 2 V- M( Y- U8 E  T$ ?% F9 y6 @0 b7 J) x
weight any 2 sets.
% h/ W2 V# |- B# N; {if the 2 sets are equal, then you know the heavy one is in the third
* [& S, P1 h+ }. M" w( xif one of the 2 is heavier, then the heavy one is in that set
! f& i5 ^7 d/ R4 Athen divide the 4 balls into 2.
* Y9 {+ B# H( D, Z, F, d5 h3 K2 J  x公仔箱論壇weigh themtvb now,tvbnow,bttvb- b* p, [; q( G
and divide the heavier into 1
; i4 t  b/ |) M( {0 J+ t, Uand weight them.% T" Q7 J- c# F- P+ t( f8 r4 T: [
3 x weighing and get the ans.    Z* V! g' v5 Z
in less than 15 secs.
1. 6 aside and weight.
* X, ~7 F3 H/ L+ H8 I! t5.39.217.77:88982. heavier side from (1), 3 aside weight again.
$ o5 G( n, R  l/ L* J6 c' t5.39.217.77:88983. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.77:88984 s* \  i5 x3 M# X# g

3 W5 K" Q; C/ p- F" }. M* i8 `5.39.217.77:8898but i have a question. 重量異常 can be heavier or lighter.... so......
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