4 vs 4, two case => a)same or b)diff.
9 H: ?6 U+ c( f' z. E. L2 [5.39.217.77:8898a)the not weighted 4 have the target, take 3 to weight with normal => same=the forth is target, diff. can let us know the target is heavy or light, weight two of those contain the target will let us know the answer tvb now,tvbnow,bttvb3 ?% P' B5 X& q8 Z1 f# Q& |4 m
b)diff. result will have light and heavy again 4vs 4, C vs D C=(3 normal + 1 heavy), D=(3 heavy + 1 light) => again 2 case same or diff., For diff. if C is heavier, than the target is that put in C, if D heavy, the 3 heavy can be weighted with 1 vs 1, heavy one is the target... For same, the target is in that 3 lighter ones, weight them 1 vs 1 will let u know the answer... |
發表於 2010-10-11 09:27 PM
| 
