zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次! k$ _* f2 W  M. Y. T6 A8 V
将比较重的那份再平均分成两份成一次
, [' i( T: }  n& X0 n剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 45 D, Y$ R3 I$ }
if  (4v4)= same that means the rest of 4 is got more weight) f6 R9 v8 G- D0 R& F& v6 B
    then goto 2 - compare rest of(4)  - 2 with 2 : X7 y; F" V. u
           if (left side is more weight)
4 u/ e% g: u0 L# u5 f% w              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer0 l7 a- c* t9 Q
          else ( right side is more weight)公仔箱論壇! t0 q6 U4 L% F2 ]/ F/ O
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
4 `. f  }" n4 T3 I. [else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。