zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
1 ]# G6 V+ x" l) k7 u# k& r/ ]公仔箱論壇将比较重的那份再平均分成两份成一次5 O4 Y$ h9 Z9 m: Z& F6 ~% o, \
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
$ m9 c; E. j( P% jTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。if  (4v4)= same that means the rest of 4 is got more weighttvb now,tvbnow,bttvb0 d3 u' z* V! L
    then goto 2 - compare rest of(4)  - 2 with 2 * F# `, g' y7 |6 g& `- I4 [
           if (left side is more weight)
: K  j, I/ d9 j. x5 M, F4 ?# R5.39.217.77:8898              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer5.39.217.77:8898$ R4 B2 ], V* O& O3 P
          else ( right side is more weight)
: U. N7 c) W5 E6 ?; x7 ~tvb now,tvbnow,bttvb              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.77:8898) d0 @3 r0 h" P* i) q9 l
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。