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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
( \8 s5 {7 [% g: r% F将比较重的那份再平均分成两份成一次. u5 t6 W: A3 I. v5 S' {
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
2 ^! R. A0 y  U  {5 ^if  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇8 Q" T" N) m* \5 g( h% c" v
    then goto 2 - compare rest of(4)  - 2 with 2
( @$ M! U2 n0 @! K; n5 `: ]3 j公仔箱論壇           if (left side is more weight)) k2 t$ b! h: t/ U3 G
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answertvb now,tvbnow,bttvb; _, I. _- |$ _  g/ h; S0 k
          else ( right side is more weight)
; I1 w$ K# W- i; E' M5.39.217.77:8898              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.77:8898. [1 f- @0 l$ L2 w5 A& S2 q
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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