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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次* H4 z% M& R. A, d! p
将比较重的那份再平均分成两份成一次# c% _. w6 c& `2 l" Z; U
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
/ s; ~% T' `1 [公仔箱論壇if  (4v4)= same that means the rest of 4 is got more weight
: a5 e. R3 Q% l9 v: {公仔箱論壇    then goto 2 - compare rest of(4)  - 2 with 2 公仔箱論壇! a5 q! S" e( M5 n
           if (left side is more weight)tvb now,tvbnow,bttvb( S4 e6 w4 e7 P, S- E7 W
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
6 v0 W6 J* q% [% T          else ( right side is more weight)
4 H6 T/ }" l* p5 _: e9 H. ]+ U公仔箱論壇              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
, g: m: F! D5 A5 Utvb now,tvbnow,bttvbelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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