zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次5.39.217.77:88988 y6 y# s- r# I0 a2 v& M
将比较重的那份再平均分成两份成一次5.39.217.77:8898- `# s8 v0 N7 H' h6 ~9 g- z( E
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
. ~  R# E: g; Q; y) A7 xtvb now,tvbnow,bttvbif  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇, ^: ]7 `: _' C7 ]  v0 a! ]7 r
    then goto 2 - compare rest of(4)  - 2 with 2 0 l9 M  i9 e5 M+ k# I
           if (left side is more weight)
$ F# _$ g" H& j* I5 R              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer5.39.217.77:8898" q( i& b6 [" M0 Y3 B( V
          else ( right side is more weight): X, @. Z% g+ H' e
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
/ H: I* Y1 z6 t2 D: s: h/ k5.39.217.77:8898else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。