zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次公仔箱論壇: s- T+ M- A6 ^2 r% e# p  j4 s
将比较重的那份再平均分成两份成一次TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。( `6 Y+ J4 Y. X) F( L) e
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4公仔箱論壇) _2 S# o2 H. G4 A
if  (4v4)= same that means the rest of 4 is got more weight
% [# X# ~! L, Z' @* b5.39.217.77:8898    then goto 2 - compare rest of(4)  - 2 with 2 % ]  h) g! t+ q" Z  U, p* O9 J
           if (left side is more weight)
2 h8 X) S1 F6 a4 y; B+ e% Z. s& Z6 h5.39.217.77:8898              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer* I' q; x9 P$ l+ P$ E) ]2 p
          else ( right side is more weight)
- i. s% @6 z- L/ b* Jtvb now,tvbnow,bttvb              then goto 3 - compare last (right side of (2) - 1 with 1 => get answertvb now,tvbnow,bttvb; `) ^3 L/ m& B& N) _9 N/ o. ]- m
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。