zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次: V- X" r) H" k) K6 X! N+ h6 u
将比较重的那份再平均分成两份成一次5.39.217.77:88983 l  T2 J* K: w! f3 B
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
$ K. o- T9 L" k/ w5.39.217.77:8898if  (4v4)= same that means the rest of 4 is got more weightTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。; L9 e5 D# A/ E# }4 x( E. ^2 i
    then goto 2 - compare rest of(4)  - 2 with 2 公仔箱論壇% Q9 S! F+ ~; Y! ^% S1 ^% p
           if (left side is more weight)tvb now,tvbnow,bttvb8 D+ `2 J% d0 w# h" |+ s# l( K
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer5.39.217.77:8898- Q$ R! F- z* V% ]$ ]7 i
          else ( right side is more weight)7 g! h& n5 L* U4 f/ V& f! ^+ ]  h
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
* o, W! q) z' Q0 b# x& stvb now,tvbnow,bttvbelse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。