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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
; b0 b1 U) ~5 h1 \  Ktvb now,tvbnow,bttvb将比较重的那份再平均分成两份成一次! ?. g' m. w9 P% G/ r6 p
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
" t; U7 ^+ C, S0 z5 `' w; Kif  (4v4)= same that means the rest of 4 is got more weight3 @( ]* c, j8 g
    then goto 2 - compare rest of(4)  - 2 with 2
( I) B' y/ K* l1 l. C, f4 }公仔箱論壇           if (left side is more weight)& s& F# o2 p1 D  L1 B" b: s
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
# x2 q/ x% C: E/ Y* Z2 ?7 I+ _tvb now,tvbnow,bttvb          else ( right side is more weight)公仔箱論壇, p. ]0 p( ]4 z' o4 s4 r
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answertvb now,tvbnow,bttvb( E" S- q% v: ]$ c9 k
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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