zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
* P. T' D% a( S! w1 {8 @公仔箱論壇将比较重的那份再平均分成两份成一次TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。6 n+ H& }/ W3 V2 Y
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
3 [$ V" q6 G! @/ X4 a0 c- zif  (4v4)= same that means the rest of 4 is got more weight
# Z' `& L1 z9 J1 n    then goto 2 - compare rest of(4)  - 2 with 2 & i; L$ A* W. ]: w: l
           if (left side is more weight)5.39.217.77:88984 p! `* ~9 I( `0 H: n, G
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer6 s6 S: L3 L# }4 z0 K
          else ( right side is more weight)" R1 f( }5 {0 V9 }! c, m
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
9 e0 [. |8 D3 Uelse ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。