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直接看答案!
i find one solution that is similar) [1 g) B7 h! K7 Z7 e
but i can't specify the heavier one is abnormal or the lighter one is abnormal when the case that has only two balls left....
' q* S1 o" k/ H% R# z& i3 jmaybe there is a better one, let me see sin
it is already good IQ if you can understand the answer......
pretty difficult... needa see answer
!!!!!!!!!!!!!!!!!!!!!!!!!

回復 #1 MagicAndy 的帖子

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thanks for share:onion14:

wow

is that really possible, i want to know
interesting ...
.... thx for sharing !
ddddd
actually this question always have someone asked, the calculation is very complicated, should give a no. of each ball, and first weight it in 6-6, and .... forgot...
how oh???
Let me see the answer
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