yeelam_168

好難呀:onion14:

chia87

see answer

jay123

Thx thx

shin0_life

阿斯打双打搭档

iio5

thanks:024:

satoushi

:onion31: ;川

tcmhw

divide 12 into 6 one side n balance it..
4 O/ I' j$ ?3 R! m+ K% Y  _0 oden take da heavier side which is 6 n divide into 2 parts again..5.39.217.77:8898: [/ [# k; v( ?, k/ A7 u" X
3 one side n another 3 another side..5.39.217.77:8898) B5 k; ]6 z" y7 g  U" Q7 p
den u take da heavier part again..7 y5 C1 D  L1 b* o" d
now u left 3 pingpong.. u can simply choose 2 of it n balance again..
: \( b- B5 }2 ?* q% }+ z2 ~( i' s) J) pif one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan

umc8800

thank you

giggs8171

so easy... 1minute can get it already...keke:onion05: :onion05:

yummyyummy123

ok啦~~~~~~~~~~

kkhc

Let's see if I got it right.

thomas_ngan

haha?:sleeps:

jw324

多謝分享

bintang118

seeee

如果可以

let's see