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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb' [4 b. t2 A& N/ R. X
1st u divide the ball into two group (i group 6 ball)公仔箱論壇& [" O6 j. g$ j: p1 ^) R
then 称 them c which side is the heavy 公仔箱論壇7 r4 G# v% F9 E/ G  Z2 ^0 Y' o
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
. ~8 i. q5 t" o8 zif not balance take the heavy and then ' Q0 `* B5 w+ \3 {4 N+ h3 Z
take the heavy group divided into 2 group i group contain 1 ball than 称 it TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5 p' _0 H  |, Z
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 2 k8 i+ P1 U2 a* [
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边2 N4 V' X/ M& O! B. v* T
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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