hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^0 Z, x* H1 B" N+ y, U
1st u divide the ball into two group (i group 6 ball)
8 e% n( ?) |  k6 [6 A& E8 q5.39.217.77:8898then 称 them c which side is the heavy
2 j2 n/ J/ m0 |: h* e! k" K5.39.217.77:8898then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 9 ?9 ]. u- S* i6 ?# a' _
if not balance take the heavy and then 5.39.217.77:88980 x3 P% O! j/ n4 M. d" Q
take the heavy group divided into 2 group i group contain 1 ball than 称 it 3 K3 X9 L' v# l+ n
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇" q( o* ~0 J! h7 ^. c/ E/ E, z& ?
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边1 r  t/ `$ i  f, A) g) H- N
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me