hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^. Z- R$ c6 u& |
1st u divide the ball into two group (i group 6 ball)公仔箱論壇5 Q6 q4 [/ C( L1 t+ {! z
then 称 them c which side is the heavy 5.39.217.77:8898$ j& U1 C" s& x3 g0 w* b
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
3 r* j. u5 E0 H# v! e5.39.217.77:8898if not balance take the heavy and then
5 ~# F* P; l: e. d5 O( Ntake the heavy group divided into 2 group i group contain 1 ball than 称 it
5 {7 p, K$ O( _! rthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
  h& {7 A" B$ ~1 h6 y7 a7 \+ ?7 E（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
& i7 s6 q! C: c, k0 I: G然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me