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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^5.39.217.77:88980 F5 o1 G9 f' k" h- j7 a" \: E
1st u divide the ball into two group (i group 6 ball)公仔箱論壇( f2 d: j  A, P  D! v7 \
then 称 them c which side is the heavy
& t' g0 A: P$ y4 d. Ttvb now,tvbnow,bttvbthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb  `# b; v  j, y0 ~- h5 U
if not balance take the heavy and then
/ c; \8 `: @  J: C  \/ F. a) \, R) ytake the heavy group divided into 2 group i group contain 1 ball than 称 it
. E* f& p* k4 @8 ~% E- A7 u9 Tthan the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb. [5 n& H: B5 d6 b2 |  L
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边公仔箱論壇4 b) ~* ]4 W# G2 l6 l
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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