hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
* _* F; H8 P) v9 t1st u divide the ball into two group (i group 6 ball)0 {  v& \1 c9 Z2 M2 ~2 X1 {
then 称 them c which side is the heavy & c8 e. a: q  C5 P& X( @
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
- q$ v) c0 R' I- x; r9 N) c' ~5 \5.39.217.77:8898if not balance take the heavy and then
, I) P5 F  H& B- E0 V6 X1 Z+ ytake the heavy group divided into 2 group i group contain 1 ball than 称 it ' u" s! L& W# t
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
* D' {: H6 `- _3 [2 w6 F" S, itvb now,tvbnow,bttvb（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
1 K8 ^; ?) j5 ?5 [然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me