hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
0 ?1 v4 X0 t" C) H% d1 x1st u divide the ball into two group (i group 6 ball)) [" D( }4 H. r+ C" x9 I% {- H( v5 K
then 称 them c which side is the heavy tvb now,tvbnow,bttvb8 h' u  Y% @: y
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 9 h/ F: ?( ~0 [6 x) w, q5 n7 m0 i
if not balance take the heavy and then 8 U/ G% y8 _( a3 y% R, _7 P2 J4 R. @
take the heavy group divided into 2 group i group contain 1 ball than 称 it 5.39.217.77:8898' z' u0 v) g. L9 ]8 F( y2 C
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇, V3 w( Q+ l: S( U& ^) Q. t3 I
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边& M" E8 t# q4 H3 r) ~0 b
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me