hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^5.39.217.77:8898; U& D1 o0 Z  C1 |# r6 D- z# I
1st u divide the ball into two group (i group 6 ball)  m$ q6 J& S3 {
then 称 them c which side is the heavy
6 U4 v( d: {; \$ p( q) i- {4 gtvb now,tvbnow,bttvbthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
  m) _, |) ^8 e" d9 [7 gtvb now,tvbnow,bttvbif not balance take the heavy and then tvb now,tvbnow,bttvb* `) b- F( _/ i6 e% ?- B
take the heavy group divided into 2 group i group contain 1 ball than 称 it
: q6 m# [; e  A2 ?: b& y公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
) o( b9 x% Y$ ]" D  n8 {3 }! D5.39.217.77:8898（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
0 k4 d  B5 M- ytvb now,tvbnow,bttvb然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me