hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^5.39.217.77:88981 B. x# N& }* p8 K$ {: D4 x
1st u divide the ball into two group (i group 6 ball)公仔箱論壇; h5 q: y1 W7 x1 h
then 称 them c which side is the heavy tvb now,tvbnow,bttvb# Z7 H* B* n- N* J
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
% y4 D5 B1 k6 z7 B- n公仔箱論壇if not balance take the heavy and then
3 u& `3 f6 S3 `: N9 u公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb% G1 \3 S5 w- J  i
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: ( z( [8 [4 V4 D2 s. s0 F/ {0 T
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
( o& T. i0 X$ d$ ~; ?5.39.217.77:8898然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me