hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb1 Q5 g9 X) _' A5 m/ ~  q
1st u divide the ball into two group (i group 6 ball)
6 l; w7 V; R/ H# b7 K5.39.217.77:8898then 称 them c which side is the heavy
1 N( [6 h5 m! I# {# q1 n% e* u5 Z; U5.39.217.77:8898then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb5 f4 o4 w3 y- N3 P/ y
if not balance take the heavy and then
) h% r/ G/ J( ?公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it
% M% N) @7 ?" K4 z+ dtvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
2 c7 z$ E4 y% U7 b公仔箱論壇（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边7 R  O1 T, {1 S) R& Z* E
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me