i thing the answer is
+ o2 M5 H8 U9 z1 V v' _tvb now,tvbnow,bttvbstart with 4 on each side of the scale,this will have two possible outcome, same or diff.
$ x5 Y2 P$ h: `6 D5 ltvb now,tvbnow,bttvbIf the same then 4 that left over contain the odd ball. put 1 of the 4 to each side, two outcome, same or different again. Replace 1 from the remaining, if the same then left over is the odd or if different the replacement is the odd one. I didn't time myself but I think I take less than 30 minutes. There are two more possible out come but still need three weighing but I think I am running out of space. |