That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。; t `% c9 k) e$ X8 r
Let x = Male, y = Female, z = Child
. |6 Z# w; n8 \1 J/ s( X* O/ H+ ytvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb% \9 ?+ ?) O, d6 E) G
x + y + z = 100 Formula 2
3 K# i0 _+ d) h( q' a1 aSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
0 |7 ~' @! e! v5 s, Q5.39.217.77:8898Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
# `5 G7 }2 a+ U. g5 T4 ?% ^" p$ yFormula 4 can change into 11x + 5y = 100 Formula 5
4 J* r' z) U% C/ N9 Vtvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.9 ?. c5 K7 W7 o
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇4 w# k* i% J$ q0 b0 @
Eventually, the answer is 20 female and 80 children and no male. |