That is a very simple mathematics question.
2 R* R; [8 y' v4 ZLet x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ f0 v( b- h0 C5 Z
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb1 P, w8 ]: S% M0 Q: J, |
x + y + z = 100 Formula 2
+ F, ^% Q& X1 p% c7 DSimplify Formula 2 into z, we get z = 100 - x - y Formula 3/ t) b3 b' p0 Z0 F. f2 @
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
. F# O: A+ e' P3 t2 zFormula 4 can change into 11x + 5y = 100 Formula 5
6 n; h8 t5 H, r4 VTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
, ]0 u4 o5 V' R$ i1 C1 ltvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.3 N/ s7 D9 K, [, S5 Z1 h
Eventually, the answer is 20 female and 80 children and no male. |