That is a very simple mathematics question.
- f1 ]2 p1 _: H0 u7 e* Gtvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child
1 g5 u( l6 X0 ztvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
. m% C' }; J' Y3 A( t3 x# u% S1 q+ i公仔箱論壇x + y + z = 100 Formula 2公仔箱論壇+ M Z% M9 C8 @7 I( Q
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。# ]8 t& t: r- b6 j' }
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb; W8 l' u# W1 _& ~
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb8 |8 h5 }3 Z' l( h. j7 ~
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
/ x/ x& p* q0 W1 ?/ \3 F( ]And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
' a2 } V0 Z* Q: h: _5.39.217.77:8898Eventually, the answer is 20 female and 80 children and no male. |