That is a very simple mathematics question.
F/ k& i w! ~. ^2 J aLet x = Male, y = Female, z = Child
$ q! ~7 k' q7 u" I# Ktvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) D' c! e# C, Z4 X
x + y + z = 100 Formula 25.39.217.77:8898( ?# k" m4 j# E8 K( y, J' C
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.77:8898* [2 I8 H% V/ W/ W) X k
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
) L* ^0 m+ i) m# k" v公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5: o; @ Y! @4 {. h$ m9 R, c! P
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
0 x R4 G' J* ]TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。* G) p2 H9 u; L
Eventually, the answer is 20 female and 80 children and no male. |