That is a very simple mathematics question.
9 r1 P4 H2 Y$ c1 _6 C: S3 Ztvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child: B# u7 S- b7 P% n
6x + 3y + z/2 = 100 Formula 1公仔箱論壇/ I$ j+ ~1 @; [0 Q
x + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5 |9 w9 i- D' c
Simplify Formula 2 into z, we get z = 100 - x - y Formula 39 S* D6 p3 T1 d- x
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇! {% j2 [; Z: M* ^
Formula 4 can change into 11x + 5y = 100 Formula 5# V; \" `1 H( Q$ z0 \1 p
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
, g2 o) q4 m8 H# ~, x- P2 rAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.8 X, {2 O( C4 H0 o
Eventually, the answer is 20 female and 80 children and no male. |