That is a very simple mathematics question.
, z2 @. _4 U- y4 B' B1 y6 xtvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child M) ^. B4 z6 _
6x + 3y + z/2 = 100 Formula 1
: I9 ?( c; k$ Q3 \5.39.217.77:8898x + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ \0 M1 W* y: n% k
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇; X: W. ?! y1 s( m2 ]& x) N- n
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 46 f/ Y4 R) B% h2 ?9 [
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇9 Z# E% _9 z" ]# H7 Y
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
8 s+ B6 k, ^+ ]TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
$ ^+ t" M+ \+ I7 ~' H$ |Eventually, the answer is 20 female and 80 children and no male. |