That is a very simple mathematics question.5.39.217.77:88989 A. L- v3 j* `- Z Y Q
Let x = Male, y = Female, z = Child
" |7 _: s$ l9 P# _5.39.217.77:88986x + 3y + z/2 = 100 Formula 1
8 ~4 V% c1 w* z$ h8 ~& e0 Rx + y + z = 100 Formula 2
5 A# ^0 Q; ?. m9 O5.39.217.77:8898Simplify Formula 2 into z, we get z = 100 - x - y Formula 32 A' g. R6 K% ~' r) K
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb5 ]+ g( M: r5 _" m! N8 M6 q
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.77:88981 z5 c0 ^# E# ~; z; G C3 q
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
- z2 i$ L' n: _: t- h& d3 [" |And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
+ ]* q" {% ^6 Q& M7 @TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |