That is a very simple mathematics question.5.39.217.77:88984 I' K- R- K; O6 H8 o
Let x = Male, y = Female, z = Child- G) b# ^, E6 ? c
6x + 3y + z/2 = 100 Formula 1
: w7 h1 x/ {6 l9 [; h公仔箱論壇x + y + z = 100 Formula 2
& V U3 G+ U0 z0 P1 V3 \& I CSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
! V7 k& f5 g1 R' @公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
* s1 v4 H* E* {# J( Btvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5
0 t3 [ W; c8 u! I1 D3 A公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.77:8898" X. C1 Y/ A+ V& J8 a9 O
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.77:8898: ?4 Y' B% } A. H- z u l
Eventually, the answer is 20 female and 80 children and no male. |