That is a very simple mathematics question.
5 m$ Z v( d" Y/ ]Let x = Male, y = Female, z = Child
) \. u2 [% x5 N& {* U& ~公仔箱論壇6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb! m$ M' B6 A( K- c! n
x + y + z = 100 Formula 2
~* |1 R0 v* |1 u! ~6 p0 c公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) f; G, R2 h$ s
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。/ u s( H9 I6 `) v V
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb. q1 M! h: N A
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.% I) v2 ^' C6 Y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
6 L& s3 {# P) e* k6 M5 d& ETVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |