That is a very simple mathematics question.# C; N( G, N2 b. `) T) ^
Let x = Male, y = Female, z = Child
8 `% V+ C, D: Q( X9 r5.39.217.77:88986x + 3y + z/2 = 100 Formula 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。, U6 [9 g6 C0 C
x + y + z = 100 Formula 2
& M# Y. S" q4 c7 F) utvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.77:88984 b6 F4 @# c; Y9 r
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇" Y+ }7 E' H/ g) V8 r" @( K
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb$ [ t" B( K# i- a) y9 W# N6 T" g
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.. I }; M- t0 [- U' ?2 O
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇 c) ~$ f2 W# f7 f8 U3 Z, A
Eventually, the answer is 20 female and 80 children and no male. |