That is a very simple mathematics question.
) D1 E" F! L3 J( i4 N" _! `% eLet x = Male, y = Female, z = Child
8 s( q p: }+ P公仔箱論壇6x + 3y + z/2 = 100 Formula 1
6 V# \0 _3 K ix + y + z = 100 Formula 2
# m, k" p8 r$ P7 \tvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
/ V; V4 i! |* U+ h- `1 Ftvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb: F6 S( }; v7 _# y
Formula 4 can change into 11x + 5y = 100 Formula 5. @! Q/ j# _. G. I& n5 k l
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
6 t6 R# V4 d& l# X/ L& G, H; @' L1 C5.39.217.77:8898And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。' I" y4 x; ?) c) q/ B2 l
Eventually, the answer is 20 female and 80 children and no male. |