That is a very simple mathematics question.1 P+ j% d8 O3 I6 m
Let x = Male, y = Female, z = Child
: e7 [+ z: l1 u4 b* g; J0 g1 A yTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6x + 3y + z/2 = 100 Formula 1
! C/ _: L- [6 A5 W, D& `x + y + z = 100 Formula 25.39.217.77:8898- X* C9 Q, H, U, i+ t1 z# T1 v$ ?
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
6 S/ [9 R' L& sTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb; \" o/ n( `5 J, _, k2 N$ n; A6 ?
Formula 4 can change into 11x + 5y = 100 Formula 5
! V o% U/ H3 h) k1 M: Vtvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.$ j) g: y( d- J( D0 s# B9 M6 |
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb2 p3 Y9 W4 g( Q- r6 j% Q
Eventually, the answer is 20 female and 80 children and no male. |