That is a very simple mathematics question.
; h+ l* Q8 c* U8 a5.39.217.77:8898Let x = Male, y = Female, z = Child, b: H+ j% t4 u& T5 Y* g5 F
6x + 3y + z/2 = 100 Formula 1
& g7 ]4 p6 r6 j( U, sx + y + z = 100 Formula 2
" R# W4 R9 d2 @tvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。& P2 \. [1 x# G' z. i
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
$ Q' @% H8 l% C( LFormula 4 can change into 11x + 5y = 100 Formula 5
6 M( w7 R5 d' hTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
+ N- }: S# L/ `2 C+ IAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb5 W6 r6 T: u. o
Eventually, the answer is 20 female and 80 children and no male. |