That is a very simple mathematics question.
! b. \, H* r* E( q+ jTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child
8 c8 o! x3 F0 b! N5.39.217.77:88986x + 3y + z/2 = 100 Formula 16 r- O1 L& c9 G v9 Z5 o& w& M- V
x + y + z = 100 Formula 2公仔箱論壇+ c" D9 M; a5 l$ Z7 l6 _# [- R) E
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇* y1 ~8 [4 m$ h) p9 I
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
7 K" t1 n& G3 Vtvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇) Y0 D2 N8 X2 l
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.4 r* d9 t" T1 a" s( x5 c$ e5 n" w8 D
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.% D# ^1 L" [, Q, p+ K9 m. F
Eventually, the answer is 20 female and 80 children and no male. |