[IQ題] [數學題] 為什麼一個整數(大於六)在兩個質數之間，可總是分為六?

idontlikeapple

為什麼一個整數(大於六)在兩個質數之間，可總是分為六? (5,6,7; 11,12,13; 17,18,19; 29,30,31 etc)TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。" d2 a& s7 r  f, c( i

0 ]$ ^, ]0 h) d4 G( x/ b6 [8 rWhy an integer, that is greater than six and is between two prime numbers, can be always divided by six? (5,6,7; 11,12,13; 17,18,19; 29,30,31; etc)
- \' o& N& X! M, K8 U0 P6 TTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
0 _$ A: W# j( R4 s, _TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Answer will be provided on Sunday (19 Sept 2010)..

idontlikeapple

這是因為質數始終是奇數，所以下一個數字始終是一個偶數是可分兩。此外，每三個數字序列中，必須有一個整數是可分三。如果一個序列的三個整數包含兩個素數和一個整數，該整數必須可分三。該整數既是可分兩和三，因此，可分六。
% r# b+ Q* R  O- W/ p. B/ E. cTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
, z+ V8 z+ ]* h% LTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。$ F* r0 _8 A* v: v0 |0 i  k7 F6 Y
It is because that prime number is always an odd number, so the next number is always a even number that is dividable by two. In addition, every three number in a sequence, there must be an integer that is dividable by three. If a sequence of three integers contains two prime numbers and an integer, and that integer must be dividable by three. That integer is both dividable by two and three, thus, dividable by six.