1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 4 m, t8 k. T6 Y- k' {公仔箱論壇For 111 would be 1x1+1=2 that is 2 times of 3rd 1 ) Y- ^0 p. v& L7 \7 yFor 1235.39.217.77:8898: J$ m7 t4 D0 ^( \
1x2+1=3 that is 1 time of 35 O. A7 m& p* r u; K
1x3+1=4 that is 2 times of 22 _$ [0 e/ m$ |$ |
2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
| 
