That is a very simple mathematics question.
" l( o9 d0 w. _% H( q5 H5.39.217.77:8898Let x = Male, y = Female, z = Child
5 k9 O: N$ [2 O) [- N6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb, r' ?4 U' l- g$ z) h) Z3 K
x + y + z = 100 Formula 2公仔箱論壇1 E' [$ C4 p# S$ Z% m
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.77:8898! I& A& [8 H [: Z
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4' m/ x B* Z3 R7 u8 ^1 o: `! W
Formula 4 can change into 11x + 5y = 100 Formula 5
* k; n. X3 ~- V+ ^In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。 b1 H" f' r5 s( k- P+ A4 p7 V) K
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
3 ^- h; j9 ?* ? [; fTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |