That is a very simple mathematics question.
' f* e( K9 c0 b% O' y9 }5.39.217.77:8898Let x = Male, y = Female, z = Child( t; w9 d* s6 f' r
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb# D% A! d! T. g
x + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% |4 \8 J7 [* _& U
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
0 R. q+ d; I. x! e4 y. ], ?; RSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
$ t: R7 V1 ?/ bTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5
5 U# `" d0 m6 N! d. G+ S4 |TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
# E. t( a$ k0 ^5 K3 A4 ~( K5.39.217.77:8898And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
; v) g+ [$ J' b1 \) e C5.39.217.77:8898Eventually, the answer is 20 female and 80 children and no male. |