That is a very simple mathematics question.tvb now,tvbnow,bttvb% J4 n1 H2 S( v7 `# O4 b
Let x = Male, y = Female, z = Child公仔箱論壇3 p9 T# ~& ]1 d- E: j2 R* u* I0 k) z
6x + 3y + z/2 = 100 Formula 1
4 p1 r! }+ Z R' f/ l. @; fTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。x + y + z = 100 Formula 2
; R3 G/ F- k5 q1 [+ J, @Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
7 ?% M' u! ]3 A ]' aSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
. V, C( A. b+ C2 K% b% Y& n) k5.39.217.77:8898Formula 4 can change into 11x + 5y = 100 Formula 5
* ] a4 Z; A: K" [ k0 C6 F$ DIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want." n. g/ d3 h( A B! `" B, ~
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。# k5 x# l# P* z. B V/ ^' @
Eventually, the answer is 20 female and 80 children and no male. |
發表於 2007-10-13 05:08 PM
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