put six on each side first
7 b8 ^, d( V% ntvb now,tvbnow,bttvb' A6 b! Z, B: q
from the heavier six, split it to three on each side5.39.217.77. Z6 n7 ^8 N0 R- B, A
5.39.217.770 _* m9 [4 r: }) N: d! y1 j# j
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |