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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
2 ^( a2 G# B. q$ c% P7 ?: t公仔箱論壇共四堆
6 `7 {* j0 q& T9 j, S' ^5.39.217.77称两次得出异常的在那一堆,其轻重公仔箱論壇" W( m: B* J% c0 c$ o0 f
在异常的那一堆中在称一次7 `, a  M! ~' X4 t5 k5 P5 _
就可以找到了
divde the 12 balls into 3 sets of 4.
- s( X+ m; \* d% D4 A% ~tvb now,tvbnow,bttvbweight any 2 sets.5.39.217.77: Q) H4 Y% U: i: t
if the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇0 Q1 l4 C' Z" Y5 t& Q8 n
if one of the 2 is heavier, then the heavy one is in that set
9 u& G2 c( g1 T) W$ qthen divide the 4 balls into 2.
/ i- s$ x$ N- N6 x0 Pweigh them
5 d% @; b! H4 e' @( M2 w- _5 Cand divide the heavier into 1公仔箱論壇4 d6 e, W2 B4 v% {2 x; o; b
and weight them.  Y' l; V  s& W# L
3 x weighing and get the ans.  5.39.217.775 O; _$ C5 _% h. s0 T3 o& S  B9 J+ u4 ^
in less than 15 secs.
1. 6 aside and weight.
( a# x& r% f5 ztvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.
  W+ H$ `# }( y2 d. V3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.773 V7 \2 M# P6 K' b, X0 f* r$ J

8 N/ e) `* v; I6 x5 vtvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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