lux1261

答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1

lesley

^:)^ >:D<

leekh

thx

jc49

let cc

Special_Forces

not possible

sm911118

不知道要怎麼做阿??

laou

hao

jen198053

there got more simple way to do it, just read my way, the one i answered before

samkk123

the

hakis

see 了

jenfien

第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了

fxenon

how?

nyb

先分3个一堆
. u  c0 r5 k( n- t. g2 \5 otvb now,tvbnow,bttvb共四堆1 T# s% [& v7 K% w' N7 [) {
称两次得出异常的在那一堆，其轻重$ `2 j* x5 |- @0 u
在异常的那一堆中在称一次
1 y* x, z4 ~9 t8 m% N5.39.217.77就可以找到了

ceteriz

divde the 12 balls into 3 sets of 4.
. h( @0 f0 N1 m- LTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。weight any 2 sets.
9 i4 }& j4 v) z8 O+ ?tvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third; f5 k1 ]( o( r+ X5 l/ d
if one of the 2 is heavier, then the heavy one is in that set
- Y; G) Z# K0 F- O- c5.39.217.77then divide the 4 balls into 2.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。; ~3 ?/ _8 {3 w4 i1 l, f0 d
weigh themTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。2 k! ?  g# Q1 S' S% V$ ~) t1 H+ F0 R% \
and divide the heavier into 1/ v. {2 X  h- Q, p
and weight them.& E8 ?; C4 H% S5 `
3 x weighing and get the ans.  
2 T/ R, J3 \# e* J9 @3 D5.39.217.77in less than 15 secs.

kino_kino

1. 6 aside and weight.
3 c9 D9 O: h; q& Q$ \0 @9 r8 {公仔箱論壇2. heavier side from (1), 3 aside weight again.
- m2 q3 K' G+ p5 q- e% W5.39.217.773. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
1 g! f9 ^$ I$ Z$ x" D2 ttvb now,tvbnow,bttvb8 r) ~+ S  g; x3 v9 {/ N$ z! {
but i have a question. 重量異常 can be heavier or lighter.... so......