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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.77  d, y+ W" G. U, j) r, s9 I, C3 i
共四堆
" Q! U: x4 Z3 i) \! L& M4 X2 l称两次得出异常的在那一堆,其轻重公仔箱論壇( N: d2 [, u1 `; N+ S! E! f5 v
在异常的那一堆中在称一次
' d% S+ O# e8 e" C" Z0 z: Utvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4.
( l7 z7 H1 P0 E5.39.217.77weight any 2 sets.
4 }  |% x7 _* kif the 2 sets are equal, then you know the heavy one is in the third5.39.217.77% U0 S1 m1 w- J6 J* z
if one of the 2 is heavier, then the heavy one is in that set
8 J8 a6 G; w% w2 k8 ythen divide the 4 balls into 2.
# ^( q" d9 m1 S1 C8 f. Y/ Qweigh them
- U" U) A2 }; i6 L' {1 e( k5.39.217.77and divide the heavier into 1
' z' {1 h' B7 A* X6 J6 g5.39.217.77and weight them.5.39.217.77) X1 D# S. o/ F: U; s! t9 d1 p; g
3 x weighing and get the ans.  
- s2 q* z1 d& w0 x+ y7 c* c公仔箱論壇in less than 15 secs.
1. 6 aside and weight.9 n) c% R; i. O0 y% p9 i, l
2. heavier side from (1), 3 aside weight again.公仔箱論壇: c- y2 O9 _1 \. N( I! |
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
6 u& Y1 T! ]5 q9 n
; l: g9 r2 t* b' btvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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