zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
8 M1 a1 G) T. \5.39.217.77将比较重的那份再平均分成两份成一次/ s. H0 Q+ Y) B) A+ W' l7 [, D
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
' `0 d5 |* a3 f1 [$ D" U2 M5.39.217.77if  (4v4)= same that means the rest of 4 is got more weight
$ w- `0 W! ]0 q+ T  ~8 j- U  a    then goto 2 - compare rest of(4)  - 2 with 2 tvb now,tvbnow,bttvb3 x; r1 B  Z3 F' V$ c! S
           if (left side is more weight)! Q5 H8 g+ n/ W
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer公仔箱論壇# M! ]; [! e1 S( v  c5 [- k
          else ( right side is more weight)$ y1 e' M( N" U0 V& p
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.77, {" N* c- ]. L. D' o' I
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。