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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次7 `) h: @- C6 O
将比较重的那份再平均分成两份成一次
7 j3 X4 O. G/ h( W( ^5.39.217.77剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
& s) q" r) p. lif  (4v4)= same that means the rest of 4 is got more weight
! @% ~* X/ Y% M! [: ^$ a( ?    then goto 2 - compare rest of(4)  - 2 with 2 公仔箱論壇2 P) q  y! _# k! R1 ^- X
           if (left side is more weight)公仔箱論壇3 s  Q. P% i( l1 O; i% d
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
6 `% K9 q, M2 i& d          else ( right side is more weight); i. R7 i' \: r! t& b
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.777 H" M) e, n/ W$ X
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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