hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
- h6 ~: |" y! l5 G3 X  I公仔箱論壇1st u divide the ball into two group (i group 6 ball)! M# o( Y4 x6 K" ]5 B
then 称 them c which side is the heavy
) t/ `% }2 c2 T6 }  f* ?then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
& v* X8 a  w+ G! A" iif not balance take the heavy and then tvb now,tvbnow,bttvb, I2 c( w" j# Y* r  @) h3 T
take the heavy group divided into 2 group i group contain 1 ball than 称 it
( R7 }4 W) K! I" g4 dtvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
& Q1 |' k2 n( U- q- btvb now,tvbnow,bttvb（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边; ]# q6 B9 w7 V6 a9 C( W
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me