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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.77  D# a) [1 y- i- |5 j! P
共四堆tvb now,tvbnow,bttvb9 r- Z( z+ o/ A) \5 I
称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb+ m3 J: d( B( p, m6 u
在异常的那一堆中在称一次tvb now,tvbnow,bttvb; @9 V" _* c7 U( E* u1 W
就可以找到了
divde the 12 balls into 3 sets of 4.
/ t  v. \6 G3 F# c* U  f9 ^weight any 2 sets.
7 `2 o9 Q' l! s6 t3 B4 r! KTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if the 2 sets are equal, then you know the heavy one is in the third4 c: Q! ^# u* O7 ]
if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇& F, t3 Y! |; E# F- T8 x
then divide the 4 balls into 2.tvb now,tvbnow,bttvb2 ^  c. o+ F3 A7 z/ _- O' m
weigh them
; V6 C' h" Y  f/ W+ S, z) L( bTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。and divide the heavier into 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- N# }( H9 }) T
and weight them.
7 e3 M6 f) N. J! c: t1 kTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 x weighing and get the ans.  5.39.217.77- ^8 C* e1 _* \1 K% C9 b
in less than 15 secs.
1. 6 aside and weight.' J7 S3 \, T& o7 S' O& V# b# ~
2. heavier side from (1), 3 aside weight again.! J! Y- B& F4 V* V1 X: e9 u
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
( h* M7 l9 x0 L9 ]" MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。tvb now,tvbnow,bttvb7 a1 u( J; a7 I- E6 x- v
but i have a question. 重量異常 can be heavier or lighter.... so......
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