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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
4 m0 L- e: U( V2 X/ ~9 _tvb now,tvbnow,bttvb将比较重的那份再平均分成两份成一次公仔箱論壇. j8 v. O( r$ V! J; G( L
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
0 `- J5 o5 }5 _; Atvb now,tvbnow,bttvbif  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇& U7 W1 L: P* o4 i! k2 X: f
    then goto 2 - compare rest of(4)  - 2 with 2 9 Z8 g- E5 B) e% t  f
           if (left side is more weight)公仔箱論壇- k) U. a. F- `. Y  ^
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
# a' g1 [; M/ I) K* ~, g: _          else ( right side is more weight)公仔箱論壇* x/ [0 |9 h4 k& q$ V- L0 Z& G
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.778 v! n! ?. U% }4 O- l7 {1 N
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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