That is a very simple mathematics question.
. s* u3 E0 i! Z. X; L% W+ b/ u公仔箱論壇Let x = Male, y = Female, z = Child5.39.217.77, D0 C9 W; [+ |$ I' Z w: r
6x + 3y + z/2 = 100 Formula 1
3 o% S# o, |# R S# Z公仔箱論壇x + y + z = 100 Formula 2( H6 ?& z7 J7 y# j
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
7 Z" ]0 b& Q) a# x: X |! X公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。" p& P1 P, ?4 v+ i, c5 M9 p
Formula 4 can change into 11x + 5y = 100 Formula 51 V/ E% k H$ C; }
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇4 P$ Q+ `* b1 R8 `8 }
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.77! V: ?0 E! H: V6 F' |2 R( |
Eventually, the answer is 20 female and 80 children and no male. |