That is a very simple mathematics question.
S( V5 J3 U" j- N/ @( `% K5.39.217.77Let x = Male, y = Female, z = Child
5 k. q( |) @* L( x6x + 3y + z/2 = 100 Formula 15.39.217.770 j7 }# e* F. L9 D: S s m6 v
x + y + z = 100 Formula 25.39.217.771 e E! b t: L+ `+ ^% x
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
9 O% \9 ]3 w6 |" x; R0 zSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4! i4 Q3 b2 M! ~
Formula 4 can change into 11x + 5y = 100 Formula 5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。9 p9 c* ^8 a& a, U5 _4 @! Y
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
& A& g! [* @ \% ~3 qAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
8 ]6 r# `/ t& S' J( mEventually, the answer is 20 female and 80 children and no male. |