That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。0 I+ q) U6 M6 X# b/ V; }
Let x = Male, y = Female, z = Child
* u/ r! C% I3 R6x + 3y + z/2 = 100 Formula 15.39.217.77' i5 u$ P" z k5 H$ l p$ U8 g2 Z
x + y + z = 100 Formula 2
" [& t1 B+ |8 |; Rtvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3tvb now,tvbnow,bttvb, x" u# R8 Z3 O- d# `" m0 m
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4% R' E3 h* y4 r, p( X# Q' | n. T
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.77# b3 l$ b6 k) e/ N
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇1 V3 H+ R! p! D! @- ~9 c$ o
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇0 t! |- ?, X3 I/ N' C- v
Eventually, the answer is 20 female and 80 children and no male. |