That is a very simple mathematics question.5.39.217.774 m& I2 g% o+ j# F) V: `; ~+ X! k( O. D t
Let x = Male, y = Female, z = Child
) U6 k J- q5 V. [; |6x + 3y + z/2 = 100 Formula 1
A3 g8 s" V+ h5.39.217.77x + y + z = 100 Formula 2tvb now,tvbnow,bttvb% G- h, [9 |. B( \
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
2 e$ _! ]# x' j3 Z2 D+ pSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
5 l8 L1 W) @8 a m6 U( b# FFormula 4 can change into 11x + 5y = 100 Formula 5
( s1 n/ N2 f; @) Q0 @, h! _: NIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.775 `0 Y0 y1 ^9 g
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
* m* w5 M& W0 @! }tvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male. |