That is a very simple mathematics question.
: G# E) v- h" O m3 dtvb now,tvbnow,bttvbLet x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5 H0 ~& }5 N; z: I N4 i1 m, x
6x + 3y + z/2 = 100 Formula 1
5 A) a; d. `7 R e( Q: Wx + y + z = 100 Formula 2tvb now,tvbnow,bttvb% s5 `5 k' J3 N$ C+ w
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
$ w2 u+ y8 X) m( {' g+ RTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇 n( y6 X7 U5 G; b
Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.77* t( X& h- \9 @. S
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
4 N, |- E% t' ^$ t, B+ h6 s: A0 \' d5.39.217.77And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
' a: J- n8 A* a' g5.39.217.77Eventually, the answer is 20 female and 80 children and no male. |