That is a very simple mathematics question.
$ H0 f. \: z9 ]% t5 g9 D& ]TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child: J& \0 Y/ r- Z; T
6x + 3y + z/2 = 100 Formula 1
+ R* x, C5 X1 D4 a* f+ F公仔箱論壇x + y + z = 100 Formula 2
$ V% v# N+ \4 G6 ~9 v% f+ Stvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 S9 \5 q% [8 ^% C1 i
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 h( P! ?0 A; E3 J6 s% j1 E
Formula 4 can change into 11x + 5y = 100 Formula 5
Q$ J) }" `: Q$ e! s- `5 LIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
% Q; w9 ?+ a, T0 mtvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.77" a: t+ q6 i+ t
Eventually, the answer is 20 female and 80 children and no male. |