That is a very simple mathematics question.
' U8 b, k" u" gLet x = Male, y = Female, z = Child8 E4 v: [: Y7 }' w$ a9 R
6x + 3y + z/2 = 100 Formula 1
# T3 Y# `$ r3 F: v4 gx + y + z = 100 Formula 2
" @1 D( r$ }! a3 P2 ASimplify Formula 2 into z, we get z = 100 - x - y Formula 3
+ R9 S0 z& t0 e. w( L: Xtvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4% ?2 V0 m+ i+ a# `* p3 Q9 }. s: w! S
Formula 4 can change into 11x + 5y = 100 Formula 5
$ Y# S2 g9 b5 I" v1 Y- i. t5.39.217.77In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.0 g Z R- u) R) O! U6 n5 J
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇- s6 B) u: _; a5 z
Eventually, the answer is 20 female and 80 children and no male. |