The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
. }# n7 ] z0 |- I% y* n5 p; Otvb now,tvbnow,bttvb; C. _3 \6 g1 @0 A" Y
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. 公仔箱論壇: ?" M% ?+ l) Q, E5 b, o* f+ j
6 i7 V. k& Z4 L3 A2 u. |3 b wtvb now,tvbnow,bttvbNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.0 K1 l' W: d# p
3 U# p8 z; Q: `5 ^0 r2 l
#3 did the obvious choice 40 divided by 2 =20, so he picked 20TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。( [6 j( H5 U0 `& e8 O- ?
2 J6 G% y% w1 }! w9 T#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。( d3 {: v7 o0 c4 o
$ o ? i. d7 _# K; E% |#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.3 D4 O+ K$ S& S" G5 R# Y1 d3 \
& z1 P' E: B V8 B) A0 [& @; ] aEnded all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
) Q) |. d1 C- n i; |/ b
