That is a very simple mathematics question.
- a, i+ U! ^" V! F* n' fTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- z. f( m/ O+ o8 A
6x + 3y + z/2 = 100 Formula 1
* K- i5 {! g8 @4 y' Q+ c- ZTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。x + y + z = 100 Formula 2
7 T& g' W; [7 F9 a) cSimplify Formula 2 into z, we get z = 100 - x - y Formula 3公仔箱論壇6 Y8 o/ q3 Y3 ^+ Y
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
6 z( W: o+ r% e3 E- Wtvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 55.39.217.772 u2 x8 m; {' v. S( a& z; o% U$ X
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.770 ]0 E/ H. _" V2 ~& B
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
$ g! J; F5 b$ x! i( _- r% o/ gtvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male. |