That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: L8 A% b- v7 k6 I5 U
Let x = Male, y = Female, z = Child
8 G- U$ {( f& b# ~: w6x + 3y + z/2 = 100 Formula 1
* I- ~1 Q/ n3 J. P7 n: T4 a5 o公仔箱論壇x + y + z = 100 Formula 2
0 Z$ y* d% I/ |/ F, i公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 39 B+ O& |0 c8 S0 c' f; z2 }+ u
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4. W+ r& E% v! {7 f0 K" Y% s% V
Formula 4 can change into 11x + 5y = 100 Formula 5
z$ ]4 @: X+ F5 O, X0 P1 b5.39.217.77In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
( o' S' M: z5 w+ r- Otvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.$ ?# l, p7 p1 Y
Eventually, the answer is 20 female and 80 children and no male. |