That is a very simple mathematics question.
; _3 _/ S8 @1 d$ G# _, I% O. xLet x = Male, y = Female, z = Child
( h" J! I9 C7 s3 F7 W* l1 JTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6x + 3y + z/2 = 100 Formula 1
: M; Y, A& w- T公仔箱論壇x + y + z = 100 Formula 2
7 H! S% L2 C) K/ Z2 pSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
- x/ d4 u4 a% s, M! S2 j I7 S公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
& O( ~! K/ J5 Y) R6 A$ qFormula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb/ P/ S3 I9 t( o* f
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
' D. u1 |% V8 D9 I5 Q0 _& }TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb6 p* c9 t C$ i0 [
Eventually, the answer is 20 female and 80 children and no male. |