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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.770 z  |6 Q% T- q" h
共四堆/ e  o; _0 T0 X( t* l/ M
称两次得出异常的在那一堆,其轻重5.39.217.775 t: j! U8 a# J) D5 H/ Q1 s
在异常的那一堆中在称一次
$ m8 [. T) Y; _# ?5 z. Btvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4.
( H- u9 `& N8 k" Z9 L2 G* q: c公仔箱論壇weight any 2 sets.) f' D( S% m. h7 C
if the 2 sets are equal, then you know the heavy one is in the third
! Q+ J1 j$ |1 A7 W/ J5.39.217.77if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇9 M; M- K1 s: h$ M. T, M+ J
then divide the 4 balls into 2.1 a5 \1 o; L3 O' e0 z
weigh themtvb now,tvbnow,bttvb3 ]0 l* T9 T8 S; ^4 \6 p! x
and divide the heavier into 1
7 r0 g0 T& L/ U) @  L* }8 o& Hand weight them.公仔箱論壇4 U! X6 }- I2 j4 W8 i) J
3 x weighing and get the ans.  
! N4 S; z7 r, Iin less than 15 secs.
1. 6 aside and weight.tvb now,tvbnow,bttvb  D9 E* S; V+ ~; v, b/ \
2. heavier side from (1), 3 aside weight again.
( y. z9 P. ]4 X' B5 `5.39.217.773. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. tvb now,tvbnow,bttvb3 E2 Y7 I& M% R, T- p; K! I; q* j" X# r
公仔箱論壇/ i+ s, C" R8 e4 V  P! t, e& f1 G5 v
but i have a question. 重量異常 can be heavier or lighter.... so......
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