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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
1 h1 T1 N+ p- g' l' }( g& A1st u divide the ball into two group (i group 6 ball)
( d! ?& M- y# k! G+ c5.39.217.77then 称 them c which side is the heavy
. ]: w" c! w  G: w/ u1 Qthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
' o+ l% _) @% T  Y6 l9 B' I% r1 [tvb now,tvbnow,bttvbif not balance take the heavy and then
- W; ^4 J7 ?# _% B9 T5.39.217.77take the heavy group divided into 2 group i group contain 1 ball than 称 it . Z7 h6 ~% a3 R* J' O' P4 \+ q' g
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇! n! {" B! ?8 F% G
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边公仔箱論壇2 b8 D$ e$ o' B$ N3 j/ i
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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