1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 4 i5 E9 v: \9 E5.39.217.77For 111 would be 1x1+1=2 that is 2 times of 3rd 1 3 y0 V8 W' g4 {! X. k: Y5.39.217.77For 123 4 \$ U0 D; s- j5.39.217.771x2+1=3 that is 1 time of 3 ! j/ A6 B5 d+ i" Z$ q1x3+1=4 that is 2 times of 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。8 Z) _* a2 a8 [' V6 \
2x3+1=7 thta is 7 times of 1