1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 * i9 ] E( D# M6 BFor 111 would be 1x1+1=2 that is 2 times of 3rd 1 ) v/ g" e& I- U* |$ a2 GFor 123 # \3 M; w% N' [1x2+1=3 that is 1 time of 3. M/ r4 ]' G0 n B8 h
1x3+1=4 that is 2 times of 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 w+ c! [8 c/ N! r W
2x3+1=7 thta is 7 times of 1