1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123# X: V! |; z& J
For 111 would be 1x1+1=2 that is 2 times of 3rd 1 V6 V T, z- D/ s/ J- i公仔箱論壇For 123 $ ~! c: d4 P n8 _* m( ?& F( q5.39.217.771x2+1=3 that is 1 time of 3 7 a6 |6 p- k( g9 b: _公仔箱論壇1x3+1=4 that is 2 times of 2 ) b* {' \! @7 K. J3 V, Y5.39.217.772x3+1=7 thta is 7 times of 1