返回列表 回復 發帖
答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆% U, A+ M& O; I3 T- @% k4 ]6 C
共四堆5.39.217.776 r% \5 c. ]7 [7 S9 M: z
称两次得出异常的在那一堆,其轻重公仔箱論壇+ }+ H! m/ D& d1 c* j: p
在异常的那一堆中在称一次tvb now,tvbnow,bttvb+ O8 R* o( z0 F
就可以找到了
divde the 12 balls into 3 sets of 4.
) p7 i0 Z" J& l, r! P公仔箱論壇weight any 2 sets.3 ?- X3 H& B) `: M! B
if the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇9 n$ N8 K% Q; j5 t" b
if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇: v' {3 {& _; X- m0 {/ A
then divide the 4 balls into 2.0 }0 p/ _' A2 G+ [1 P: z0 j& Q* o
weigh them+ b' n$ a0 Y6 v$ O3 g8 s
and divide the heavier into 1
4 }. A/ i! `# g# C( f2 W5.39.217.77and weight them.tvb now,tvbnow,bttvb9 O6 P+ P: v2 O* c' ]0 [2 i0 q
3 x weighing and get the ans.  
: H2 d5 M( q) sTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight.
  m8 i$ L9 g# w- b5 J0 NTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2. heavier side from (1), 3 aside weight again.
  N9 P4 A; B; `# \+ h5.39.217.773. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. * q5 s% e* e, s9 r& P
5.39.217.777 `% E, b$ m7 X4 I# y
but i have a question. 重量異常 can be heavier or lighter.... so......
返回列表