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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
" M% }* Z! t0 p9 R  ?) S( E/ L' C共四堆8 [. ~8 I; E% s, p& z  d! ~
称两次得出异常的在那一堆,其轻重- a6 a$ x' L/ {+ \. }' U
在异常的那一堆中在称一次  A, @0 w$ l! j+ e7 z5 e8 J
就可以找到了
divde the 12 balls into 3 sets of 4.
  A: Z$ P! `" m9 B! ]# mtvb now,tvbnow,bttvbweight any 2 sets.公仔箱論壇" Z& k! M' s# ?7 \2 d  {% p+ F
if the 2 sets are equal, then you know the heavy one is in the third
. B% r2 J/ v9 k0 X- J" U5.39.217.77if one of the 2 is heavier, then the heavy one is in that set
" v  g: c! }# V  t: i, [0 i1 rthen divide the 4 balls into 2.
# n+ l% d# N" O" l8 V* W公仔箱論壇weigh themtvb now,tvbnow,bttvb4 d5 o( E8 A. J
and divide the heavier into 1; O8 p3 P) f+ A9 Q# B9 V7 B
and weight them.$ G  z, F2 l" E
3 x weighing and get the ans.  TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) l' ], A! b& H/ b! x$ l
in less than 15 secs.
1. 6 aside and weight.
5 L" s* a, x  t6 Q+ N2. heavier side from (1), 3 aside weight again.公仔箱論壇: t6 g4 \1 _) Z  S0 j3 d2 K- n
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
( O. {5 X1 M  H3 k/ r( y3 M5.39.217.779 f2 u5 w) P9 b/ u% B9 m
but i have a question. 重量異常 can be heavier or lighter.... so......
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