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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
0 w2 b' R- Z8 N- b8 U: d# P将比较重的那份再平均分成两份成一次
1 q- L7 `" h/ j5.39.217.77剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
4 ^, H, N( [. [9 w5.39.217.77if  (4v4)= same that means the rest of 4 is got more weight
- v. f! u4 |) H$ w' w5.39.217.77    then goto 2 - compare rest of(4)  - 2 with 2
% y0 O' F. z% N  |           if (left side is more weight)
" c1 n. y. r6 m# R5 [' d- Htvb now,tvbnow,bttvb              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
7 C" M8 Q9 ]7 M3 F) G3 e9 m2 ]& E公仔箱論壇          else ( right side is more weight)
7 I1 P4 M9 j' |; W  ~5.39.217.77              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer公仔箱論壇3 e" i4 _4 H1 Z: \5 Q
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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