hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
# E' `8 x' h% h' y; ]1st u divide the ball into two group (i group 6 ball)
& @! a' P1 h1 v; f7 F/ {1 A# K公仔箱論壇then 称 them c which side is the heavy 7 h  ~/ v( O! c/ z) @7 c
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group + o' `& A" O" e* m; k1 T
if not balance take the heavy and then
5 ~( k& C! \, _& R5.39.217.77take the heavy group divided into 2 group i group contain 1 ball than 称 it
. N0 G, a0 W3 Y0 ]7 E$ Q9 h( @公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
0 l0 n0 h2 }. I! `7 D5 I+ h公仔箱論壇（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
0 j; P' l9 i3 R7 q$ K4 F然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me