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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆公仔箱論壇+ y3 x) O2 ?& h2 p0 ^
共四堆) x* l: H; P" z7 P& [
称两次得出异常的在那一堆,其轻重5 Y: h2 n' ^" b- \0 y" a+ a
在异常的那一堆中在称一次TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。# A. M3 x0 V8 ]6 q
就可以找到了
divde the 12 balls into 3 sets of 4. 9 p9 n1 Z; R* F0 F" u9 b
weight any 2 sets.5.39.217.77/ J/ h' f6 e. \  Z& K/ ~
if the 2 sets are equal, then you know the heavy one is in the thirdtvb now,tvbnow,bttvb. e4 |, b) G8 m( Z0 o+ _
if one of the 2 is heavier, then the heavy one is in that set
3 Y) P* [0 j; m. q' G, Ftvb now,tvbnow,bttvbthen divide the 4 balls into 2.tvb now,tvbnow,bttvb3 {8 b" L& R, H
weigh them
; M. F2 y& j$ y4 L* O# iand divide the heavier into 1
- c4 K. J* s- W  w0 Zand weight them.tvb now,tvbnow,bttvb' Z+ h9 s; z- \$ J$ g, b/ x: ^4 {& w
3 x weighing and get the ans.  " J/ }) l; R) b7 X  u. ]6 O
in less than 15 secs.
1. 6 aside and weight.
" E1 ~2 y2 r# J! yTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2. heavier side from (1), 3 aside weight again.5.39.217.77% H! B7 N+ I! V7 e
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
: A' I$ @' n, Htvb now,tvbnow,bttvb
6 R; C8 c: `) ^, Jtvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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