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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆6 R8 [. _3 T9 t/ e/ h
共四堆
( l, v+ A, O* _/ f; `7 Z9 n% @3 e称两次得出异常的在那一堆,其轻重
, J6 f- ~: x3 ^- D. I在异常的那一堆中在称一次tvb now,tvbnow,bttvb+ f" Q' w% Q, T- m7 O& G& ^
就可以找到了
divde the 12 balls into 3 sets of 4. 5.39.217.77. U0 ?" }. T- ?" O2 B0 m
weight any 2 sets.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。& a: X  v  J: i$ B" ^
if the 2 sets are equal, then you know the heavy one is in the third/ \7 }0 _2 m' r: \, d+ x
if one of the 2 is heavier, then the heavy one is in that set5.39.217.77: p7 l- |& H) I2 J
then divide the 4 balls into 2.
! q+ d5 @& v2 L' v7 \8 e' ZTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weigh them
3 h# ?$ Q4 f7 Ytvb now,tvbnow,bttvband divide the heavier into 1
7 ?: R& s+ M$ {  X! m  Zand weight them.
9 q1 ~+ B/ ~  M4 ?; Z: X3 x weighing and get the ans.  
* @0 E. w( e: k* {4 o5 @2 A5.39.217.77in less than 15 secs.
1. 6 aside and weight.
! C& |& u* e+ @% P9 J2. heavier side from (1), 3 aside weight again.
* M! R& _9 w1 Z% i: P& ^: ^3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。! A2 I$ I/ H* Q& ?) r+ x
: J  Z2 F  O) R5 F# W% E3 o
but i have a question. 重量異常 can be heavier or lighter.... so......
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