firstme

easy, one minutes i solve the problem
$ z  i) v9 b4 S0 E5.39.217.77divide into half, mean 6/ 6
+ _( H; G; H$ _take the heavier 6 ping pongtvb now,tvbnow,bttvb0 X" m/ E2 h" F. E; P% F4 f' _) R" @
divide into 3/3, take the heavier 3
/ a+ W( u' K) \3 w5 c, mtake the the other 3 that have the equal weight, switch each to measure, the most important things is labeling the ping pong so that we can recognize

firstme

量３ 次， 一次 ６比６， 一次３比３， 一次１比１， 就可以找出来了