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1#
發表於 2008-10-7 12:36 PM
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use 4-4-4 .. if the first one is equal than the group 3 has the one .....and put 2-2 than 1-1 !! and u found out !!!
* z1 |0 |# T `8 \1 u9 \3 Y+ \
' r4 a+ D2 D$ {( C8 vtvb now,tvbnow,bttvb
& Y+ Q- S) a7 u8 Y5 onot that hard !!!! i only 5min !!!! |
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