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回復 #1 MagicAndy 的帖子

divide 12 into 6 one side n balance it..
, Q( S( g4 `9 e) `% k/ p! iden take da heavier side which is 6 n divide into 2 parts again..5.39.217.77+ B2 p( Q. J, D  x# r
3 one side n another 3 another side..3 D* c3 l( z  m8 N/ e. l1 f
den u take da heavier part again.., u. q& U" c- s4 g! O" ?7 u  z
now u left 3 pingpong.. u can simply choose 2 of it n balance again..
  K$ X& O& H0 cif one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan
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