number 4 has the best chance to live. Y _6 h: C; l" B# K1 p4 m# f
assume number 1, 2, 3 and 4, pick number a, b, c and d.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。4 U- `" p9 Q$ }, H- c0 X) @
number 4 knows how many left in the bag which is 100-a-b-c
2 _1 |$ g K$ ]* [: |8 ?; U: n0 P7 gTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。take the average of (100-a-b-c): k& g8 s& j3 n% z* y5 D8 `
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
( l/ L4 R. w7 W+ @TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。and number 4 can squeeze himself into the average and what number 5 picks.
, p) p e, o1 T1 Wso number 4 will have the best chance.tvb now,tvbnow,bttvb# q6 A2 m$ _. D/ f% J6 V: X5 d
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i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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