loveallcar

number 4 has the best chance to live
& x/ F& D, K9 m# H+ V) Z" E! m公仔箱論壇assume number 1, 2, 3 and 4, pick number a, b, c and d.5.39.217.77' ?1 v4 A0 }& n
number 4 knows how many left in the bag which is 100-a-b-c
/ s/ @! w1 |$ x6 W8 C' ytake the average of (100-a-b-c)tvb now,tvbnow,bttvb/ B; t# |5 M- ?( \/ T
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
( g' y3 t  N/ R; V公仔箱論壇and number 4 can squeeze himself into the average and what number 5 picks.
- e  n' f+ d& L! @  h" [9 C3 Jso number 4 will have the best chance.tvb now,tvbnow,bttvb- C9 p! g4 i, j8 h0 w
5.39.217.77/ W9 E" r! ]4 y
i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.tvb now,tvbnow,bttvb8 ?8 E* p6 b* p0 l1 r6 V$ g( `
please post answer la5.39.217.77: t5 C7 z& Z% T
can't wait la