number 4 has the best chance to live
; | _' {0 j- {; G% Q5 y0 Iassume number 1, 2, 3 and 4, pick number a, b, c and d.
# _0 }& z* M1 G' vtvb now,tvbnow,bttvbnumber 4 knows how many left in the bag which is 100-a-b-c
" P7 F1 k3 ^% x- U+ d6 \5.39.217.77take the average of (100-a-b-c)
/ c D5 p- R0 w0 ^# h Z5.39.217.77then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)5.39.217.77! w" d; w& L! t R" a; \1 D
and number 4 can squeeze himself into the average and what number 5 picks.5.39.217.77% Y+ k R2 B- Y, X4 }& i$ R
so number 4 will have the best chance.5.39.217.77; [4 M( w* Y; g1 k# i. R
]$ e6 `0 S& u& @; FTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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