number 4 has the best chance to liveTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。6 o( N. e' l5 D* l p8 _5 v6 ^
assume number 1, 2, 3 and 4, pick number a, b, c and d.
, y% Z, N. V: h5 V9 }* f5.39.217.77number 4 knows how many left in the bag which is 100-a-b-c
6 T' {* ?$ b9 I1 Z! f3 g9 `: ~8 ATVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。take the average of (100-a-b-c)TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。7 P/ S- g& e" R \" I% ^
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)5.39.217.777 `3 {* n9 ]- \2 x5 s: d
and number 4 can squeeze himself into the average and what number 5 picks.* a+ t% m* \% }7 Y7 Y" d) r4 H
so number 4 will have the best chance.
" B5 R* b4 W& X( x5 ATVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。% K+ ?0 e6 X9 t7 D4 W
i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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