loveallcar

number 4 has the best chance to live# N/ s- m5 }8 x+ h' U; w7 d0 m' E# \2 f
assume number 1, 2, 3 and 4, pick number a, b, c and d.& N! S% R- |+ a* [! _6 s* E
number 4 knows how many left in the bag which is 100-a-b-c
% s% q: u% X5 p$ c6 a5.39.217.77take the average of (100-a-b-c)
) m# y8 O8 u& j5 Z! Dthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
% g0 c- F. P( z( u1 [9 stvb now,tvbnow,bttvband number 4 can squeeze himself into the average and what number 5 picks.
5 S8 O1 d) f( W  S公仔箱論壇so number 4 will have the best chance.5.39.217.77; f/ H6 M8 Q6 f" M

' C& @1 |, Y4 j, t% Y2 l5.39.217.77i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.
* ]$ ^0 @" w8 ]5.39.217.77please post answer la, B+ Y7 O+ Z0 E8 w, t* k, T
can't wait la