number 4 has the best chance to live0 s! r$ o2 A4 X
assume number 1, 2, 3 and 4, pick number a, b, c and d.
( Y( }, f8 u0 p+ |. a; H+ m1 M公仔箱論壇number 4 knows how many left in the bag which is 100-a-b-c
. j$ c j/ j& T) A+ p9 G4 _公仔箱論壇take the average of (100-a-b-c)5.39.217.77; K( L9 U" s2 m; _) e0 S) o. J
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
/ ~8 h" U& c9 R公仔箱論壇and number 4 can squeeze himself into the average and what number 5 picks.
: n! X5 V" p* b% Dtvb now,tvbnow,bttvbso number 4 will have the best chance.
7 A" e3 s* |/ N2 h* Y7 W! {" x. _TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
" E( E- \8 {& G" @0 |8 S5.39.217.77i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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