number 4 has the best chance to live
; ]: n/ c+ x8 G; F! h1 YTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。assume number 1, 2, 3 and 4, pick number a, b, c and d.5.39.217.77$ d* v6 ]6 b: ^8 q2 X3 \0 x
number 4 knows how many left in the bag which is 100-a-b-c
4 M/ \" k- q8 X X5 Q {" nTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。take the average of (100-a-b-c)
4 W! S$ Q0 C+ K' u T6 @TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)tvb now,tvbnow,bttvb' F. e# k( C8 E0 e/ f, u
and number 4 can squeeze himself into the average and what number 5 picks.
6 @3 R; a4 |7 Jtvb now,tvbnow,bttvbso number 4 will have the best chance.
4 m- d! K+ f" N+ ~9 [0 c4 N
! h( H/ y& B1 Wi hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
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