loveallcar

number 4 has the best chance to live
& \7 q- I( t8 M- J3 S$ \: yassume number 1, 2, 3 and 4, pick number a, b, c and d.
+ \: v  c& y" C3 Ztvb now,tvbnow,bttvbnumber 4 knows how many left in the bag which is 100-a-b-c
; ]+ W* l) p; c5.39.217.77take the average of (100-a-b-c)tvb now,tvbnow,bttvb+ S( t+ ^; j$ S
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
' B0 v7 Q) \( f( y& V+ qTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。and number 4 can squeeze himself into the average and what number 5 picks.
# D) G, O" y( k" n$ zso number 4 will have the best chance.
! J6 R9 y0 {2 atvb now,tvbnow,bttvb
8 C- z2 U/ a& k% L4 C( VTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.
3 p$ E8 q; D4 d0 x) k& C  O( h8 }tvb now,tvbnow,bttvbplease post answer la
1 J  z4 _0 F% a7 zcan't wait la