loveallcar

number 4 has the best chance to live5.39.217.77% H  O; H$ z5 {7 ?+ U0 L
assume number 1, 2, 3 and 4, pick number a, b, c and d.5.39.217.77; Y. ]6 [4 k, L3 a3 b
number 4 knows how many left in the bag which is 100-a-b-c公仔箱論壇0 w/ W3 m4 i( M9 @! Q
take the average of (100-a-b-c)TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。, j8 h1 V5 q, m4 K
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)tvb now,tvbnow,bttvb+ k# [! `' B' w! E( I0 f/ z2 u
and number 4 can squeeze himself into the average and what number 5 picks." P3 A' @+ h; u; V
so number 4 will have the best chance.tvb now,tvbnow,bttvb" G" c( O& x6 {9 h: q
公仔箱論壇. u, O7 s& d+ c# t0 i& s
i hope this is a good logic hehe

loveallcar

aiya, how come still no answer ga.公仔箱論壇  v6 k, V( \$ p9 L7 o: j$ Z  o
please post answer la公仔箱論壇8 t' W; s+ |1 h7 g7 z
can't wait la