number 4 has the best chance to live
9 `! r/ A0 A1 K2 ~7 H7 @6 {! u公仔箱論壇assume number 1, 2, 3 and 4, pick number a, b, c and d.
( m8 d$ C& m B1 r, `number 4 knows how many left in the bag which is 100-a-b-c
/ e; ]/ _! E2 {5 @$ mtvb now,tvbnow,bttvbtake the average of (100-a-b-c)tvb now,tvbnow,bttvb1 n0 C% \8 ~1 l9 I; o9 F. ?
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
- _% L4 I: @% {# t1 ^4 D公仔箱論壇and number 4 can squeeze himself into the average and what number 5 picks.
1 A6 o4 n) D2 d& \3 B; m7 q% J! [5.39.217.77so number 4 will have the best chance.公仔箱論壇7 K% y# o* m/ S% c+ ^: k& a
( G: E: _! j8 B' l# C4 e
i hope this is a good logic hehe |
發表於 2006-12-12 09:29 AM
| 