mekl_2233

4 vs 4, two case => a)same or b)diff.
4 p: p' u+ a* g; O* da)the not weighted 4 have the target, take 3 to weight with normal => same=the forth is target, diff. can let us know the target is heavy or light, weight two of those contain the target will let us know the answer  公仔箱論壇7 f! R. e7 `: l
b)diff. result will have light and heavy again 4vs 4, C vs D C=(3 normal + 1 heavy), D=(3 heavy + 1 light) => again 2 case same or diff., For diff. if C is heavier, than the target is that put in C, if D heavy, the 3 heavy can be weighted with 1 vs 1, heavy one is the target... For same, the target is in that 3 lighter ones, weight them 1 vs 1 will let u know the answer...