好多答案啊``无聊的问题``作者: jamesdean 時間: 2009-10-2 06:55 AM
1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.作者: pengzw1984 時間: 2009-10-8 01:53 AM
249还有123作者: masami198763 時間: 2010-1-31 09:42 PM
123 and 789?作者: kuku88 時間: 2010-2-6 05:29 PM
three 1作者: ckpang 時間: 2010-2-7 11:05 PM
123.。。作者: cloud_FF 時間: 2010-2-9 02:16 AM
1 1 1作者: buxiang128 時間: 2010-2-9 09:55 AM
我列了个复杂的方程,但解不出了。不过如果不是1、1、1,楼主可能得注明是“三个不同的正整数”作者: khkiang 時間: 2010-2-12 03:13 AM
111, 789 ... and many many others.作者: beckyken 時間: 2010-2-12 01:48 PM
They would be 111 or 123tvb now,tvbnow,bttvb6 e- s9 U2 p/ k# P9 \; W: _3 I$ U4 n
For 111 would be 1x1+1=2 that is 2 times of 3rd 1" T6 i: p# {1 V1 a, \! k
For 123 u, c) N: F1 E1 ?4 [
1x2+1=3 that is 1 time of 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。; D' s3 ~ R- B Z6 ~
1x3+1=4 that is 2 times of 2 1 J7 o+ W3 N* I" {& d5 {tvb now,tvbnow,bttvb2x3+1=7 thta is 7 times of 1