That is a very simple mathematics question. t# F C2 v& v9 C6 |Let x = Male, y = Female, z = Child H' q$ ]; ~3 _' Y* ^6x + 3y + z/2 = 100 Formula 1 . b; a# U, H( g5 i: _" c( [0 J5.39.217.77x + y + z = 100 Formula 2/ C6 ^; u4 k: _6 V' ?0 W
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3% r+ T! @4 d v& r6 \
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 42 H! C- k2 V; ~
Formula 4 can change into 11x + 5y = 100 Formula 5 ! [$ t) \2 _: [tvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇' T S2 a' `6 T+ J+ v5 k1 Y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.77$ B- ]7 a1 u7 M# M
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
! e4 P3 P+ M& I' u* K6 Wtvb now,tvbnow,bttvb11X must be 0 or multiple of 5 ; k- @: \7 I% ]" V6 m+ L5 g: k5.39.217.77that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
86 children/ i- P9 `& {% T" V$ n# r% E
5 male Z. Q% n2 i, \( M1 U: G1 J5.39.217.779 female作者: dafunhei123 時間: 2007-10-15 10:39 PM
