That is a very simple mathematics question.5.39.217.77* ^# |0 _1 j: u! o
Let x = Male, y = Female, z = Child, [% h0 E0 P4 E6 m5 l7 x
6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb4 i' p! X( W3 r! w* j* W
x + y + z = 100 Formula 25.39.217.779 j m$ ~/ t, c4 x: @6 \) Z1 S3 `% E
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 2 x+ ^, `. }3 aSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 7 g/ B, W/ a& n2 o" @" @5.39.217.77Formula 4 can change into 11x + 5y = 100 Formula 5 J7 ~& m: r4 X5 f5.39.217.77In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. + I6 \7 ?! e9 y4 M V8 Z! nAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇6 Y/ k$ S0 k2 E. M) u
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
5.39.217.775 V6 x) i: L; ]5 V; r7 Q- R
11X must be 0 or multiple of 5 u; t) Y5 j$ n0 u, w) x
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
86 children * x; A) e, T" p+ M1 l- Htvb now,tvbnow,bttvb5 male 4 W9 F% R* h; u8 T: R4 Jtvb now,tvbnow,bttvb9 female作者: dafunhei123 時間: 2007-10-15 10:39 PM