That is a very simple mathematics question. , @# F6 H9 h" M% m0 |公仔箱論壇Let x = Male, y = Female, z = Childtvb now,tvbnow,bttvb$ o% v/ x1 x- d4 f1 w
6x + 3y + z/2 = 100 Formula 1 , p, c% K: k* h) M+ btvb now,tvbnow,bttvbx + y + z = 100 Formula 26 G' ^/ f: i' ~/ p6 G% c! R" h0 q
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.77+ H0 D& O( Y: o$ n+ x3 V
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 & U$ I" [. s8 V2 c/ u5.39.217.77Formula 4 can change into 11x + 5y = 100 Formula 5 1 p! |( u. l+ ~5.39.217.77In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. , M' h% j) {! p+ F6 a$ ]3 PAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.779 r/ n+ Q' a8 Z8 i7 l* W
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers