That is a very simple mathematics question.tvb now,tvbnow,bttvb8 c3 \. L! c6 g$ C6 ~5 b% i# I, v
Let x = Male, y = Female, z = Child _& N" k' n9 r- f4 ytvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 15 k- \2 `5 D; E) Y+ P G# k
x + y + z = 100 Formula 2 3 K6 q p7 l- e. kSimplify Formula 2 into z, we get z = 100 - x - y Formula 3 U" Q/ o/ G1 K' ?8 I1 n: s Vtvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 0 D7 ?$ s8 E. T. h5.39.217.77Formula 4 can change into 11x + 5y = 100 Formula 56 M* a9 N$ W3 q: D
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇- f0 N) r8 P8 U/ a S
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. 7 O1 |, i: a( }, xEventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
5.39.217.77$ W8 ]5 J# Y5 R3 t M# j
11X must be 0 or multiple of 5tvb now,tvbnow,bttvb- n- T6 Z* z" ^" @4 b, C
that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
