That is a very simple mathematics question.tvb now,tvbnow,bttvb! f$ k, S, C x# {. b$ T' d
Let x = Male, y = Female, z = Child 8 q; g$ o4 M/ B公仔箱論壇6x + 3y + z/2 = 100 Formula 1 , |7 _; w6 @6 b6 n, U/ w# Etvb now,tvbnow,bttvbx + y + z = 100 Formula 2公仔箱論壇0 \1 B: y. A" U$ V% V* [
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 , u8 e. |4 k# d& ?" pSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇7 _9 `" N6 |! a0 @
Formula 4 can change into 11x + 5y = 100 Formula 5 * ] d, E% W: v7 Y; {* D. D3 e# X公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. : @7 ~" ?' r9 K& k9 S5 F公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb" `, V/ D8 P8 @0 ~0 {8 g# S& w
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers