That is a very simple mathematics question. " b j8 [2 p/ v8 l @公仔箱論壇Let x = Male, y = Female, z = Child5 \) Z" z: h0 s; o" q2 @- F, m3 Y1 X+ \
6x + 3y + z/2 = 100 Formula 1 & c4 w# o+ L8 I, S y" f* a; Zx + y + z = 100 Formula 2 ( g% G6 K6 _* A5 }1 w; {5 yTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 % `+ c2 }, D8 I2 stvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 % k& ?. Z: b) N) U. W3 S5 F6 B公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5 ( E3 @0 I$ C2 p6 y公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. ( ]( `0 ]+ P% R. B5 C6 R9 HAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.+ _0 W- j! i* t
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
原帖由 twinsdragon 於 2007-10-13 05:40 PM 發表 - r ~5 u. N" l! ^+ K0 F" n
11x + 5y = 100 Formula 5
! n* i2 F: e/ y" {5 l7 E7 E2 i11X must be 0 or multiple of 5 0 L, T1 \# s7 v; F( h1 j公仔箱論壇that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM
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