That is a very simple mathematics question. 9 |$ k# `# y) z" C4 _8 x1 X公仔箱論壇Let x = Male, y = Female, z = Child公仔箱論壇/ Z/ e/ \; _/ z5 w+ [/ N
6x + 3y + z/2 = 100 Formula 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) n5 Y$ @/ u$ c
x + y + z = 100 Formula 2 5 h+ q2 t u6 {5.39.217.77Simplify Formula 2 into z, we get z = 100 - x - y Formula 3 + e2 Q) n) {4 k. E' `9 v公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 ' |7 H- S$ B8 S7 n( N5.39.217.77Formula 4 can change into 11x + 5y = 100 Formula 58 p1 R# a2 h/ f) Y- @1 g9 E' B
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.( @0 H3 \# T0 ^0 M/ D% }$ f
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.( \) s, Q. r7 W9 N
Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
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11X must be 0 or multiple of 5 7 c1 `1 k1 K! @6 w# X8 hTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM