That is a very simple mathematics question.tvb now,tvbnow,bttvb" t) Z# p8 \5 t" P1 ~# C# f
Let x = Male, y = Female, z = Child s) [! V9 g2 s: m9 v
6x + 3y + z/2 = 100 Formula 1 5 c; h1 v9 V, f- h; r2 L9 Dtvb now,tvbnow,bttvbx + y + z = 100 Formula 24 o/ H$ X& P% p: _3 [% d
Simplify Formula 2 into z, we get z = 100 - x - y Formula 32 D( J5 X6 Q* h+ U$ E
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4 / z% \' K$ q6 Q0 Wtvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 51 K$ F/ A4 r5 A
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want. 0 R* J5 _5 L `tvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80. " ^, I2 y% ^7 ~) {( c& c, h5 e0 A公仔箱論壇Eventually, the answer is 20 female and 80 children and no male.作者: alan1234 時間: 2007-10-14 12:19 AM 標題: two answers
man,female,children5 L C* c+ d5 ~( N
0,20,80 or 5,9,86作者: RyanC 時間: 2007-10-14 10:46 PM
0 h7 P; j) O. i3 v% U/ M' B# O公仔箱論壇11X must be 0 or multiple of 5 % C) i: o0 i% @* I* U, d5.39.217.77that meanz x must be 0 or 5作者: manstein 時間: 2007-10-15 08:28 PM