1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 2 Q" P% l2 [* q! P5 Q+ l: n: y4 M8 bFor 111 would be 1x1+1=2 that is 2 times of 3rd 1 2 e7 D$ k4 Z& g* RFor 123 / R$ q7 ^* `' f公仔箱論壇1x2+1=3 that is 1 time of 3 - }/ W( @% S- T& f8 u# D& S5.39.217.771x3+1=4 that is 2 times of 2 3 U$ R) y$ T+ |& S! n" Y8 e; ]' u2x3+1=7 thta is 7 times of 1