1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 7 t) P* _) }8 }/ e6 m' }$ f公仔箱論壇For 111 would be 1x1+1=2 that is 2 times of 3rd 1 r& \. t& ]4 uFor 123! {( u/ R. d6 c2 K, y! @1 f
1x2+1=3 that is 1 time of 3 Q1 K4 U& p" Q
1x3+1=4 that is 2 times of 2 4 M5 V/ x8 \0 C) @9 Q: |/ f2x3+1=7 thta is 7 times of 1