The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.5.39.217.779 W1 {& G8 x" E" e2 W# t" \
5.39.217.775 ~% A! X7 b' d' R! p4 h; O% ^
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. tvb now,tvbnow,bttvb( \3 d' X( d% R4 N) U3 X
( {$ L) u2 _! V% {+ lNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
" y$ c" z. U/ j+ rtvb now,tvbnow,bttvb- T& N3 s4 ?3 U$ ?9 _
#3 did the obvious choice 40 divided by 2 =20, so he picked 20
! O7 S/ J6 t" R- p: K+ M1 }公仔箱論壇
1 X) b* Z/ V6 i7 H2 B4 MTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
! |8 `9 Y6 g: o: p e3 a# iTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。. K0 H3 U& f& g; D' U
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。' c' y W# K7 l4 J% L
5.39.217.777 ?3 a1 h( T( z6 Z+ M8 p
Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
tvb now,tvbnow,bttvb3 A$ Q3 p [ E% `" o
