The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.8 d! c0 |% t7 |! g. r
l6 A, [ S3 k, \. I" G7 Q' Z! NStarting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。8 b: X+ }" z; }0 y, k( {# ]8 d
! F! w! g! ^8 B' J* xtvb now,tvbnow,bttvbNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
9 z3 E3 U( G: Vtvb now,tvbnow,bttvbTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。2 Q8 e% N) i; `; d5 A
#3 did the obvious choice 40 divided by 2 =20, so he picked 20tvb now,tvbnow,bttvb. o, }" i, D4 Z# C0 T% E; ]) @9 C, j% ^
4 o* A" @* s& k+ j; p公仔箱論壇#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.tvb now,tvbnow,bttvb. z7 O. {8 H* \7 m) i$ T( p
( X7 c% g: _# U# [#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.0 X2 G3 d0 b7 G, S5 F. A
4 Z' T( [; k% g- J. P' GEnded all have the same number and all died. |
發表於 2006-12-9 12:41 AM
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