The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.公仔箱論壇+ N9 i" {' c! k
6 v6 F9 t' k2 {8 y- X5.39.217.77Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。4 K' E' n# D' o" q
5.39.217.777 } `6 {6 b7 V4 M8 o, ^5 ~8 N6 \
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.6 q3 e9 L; d/ t0 m
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#3 did the obvious choice 40 divided by 2 =20, so he picked 205.39.217.771 ^" @2 X) }" W" W; j
w" m1 m$ K" u- \# n7 l( d; ]0 hTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
; ~, f* w' p( C) yTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
; \% h' ~/ @. H o#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
* W+ v" u$ q( Y* I+ ?5 Ztvb now,tvbnow,bttvbTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。+ M7 V7 j% B, r+ f2 U/ ?$ f- [+ G' ^
Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
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