put six on each side first5.39.217.77& f8 i# d0 r9 S: b
2 F6 W- ~; k1 c" L* cfrom the heavier six, split it to three on each side
8 k# p/ s! P1 m* w m" c/ ]
0 @6 @3 d: |5 S! I5.39.217.77then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |