put six on each side firsttvb now,tvbnow,bttvb5 w- _: ~: _! }$ ]
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from the heavier six, split it to three on each side* x- X9 _# j/ } p3 |5 u7 v# f; X
3 u2 b3 I h( \5.39.217.77then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |