put six on each side first
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3 u9 B, X" O* u* T" P: r/ E8 dtvb now,tvbnow,bttvbfrom the heavier six, split it to three on each side
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; N5 s9 x. R! e- l8 T+ j. z2 h5.39.217.77then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |