put six on each side first
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6 X0 l0 t! q6 Q2 Pfrom the heavier six, split it to three on each sidetvb now,tvbnow,bttvb6 z- {. P; q$ `# H
7 u, X$ c3 D& `( r2 _2 xtvb now,tvbnow,bttvbthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |