put six on each side first
0 `2 ]. ~+ b# q3 d0 R: _+ w6 D* C% h9 S- S; {3 U/ T. A$ \# R
from the heavier six, split it to three on each side
/ [& T0 p9 V9 k$ q* b公仔箱論壇/ h* t* {2 k, x3 D3 v
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |