put six on each side first
: P4 R" D- _$ p J
! T3 f$ ~2 u5 R' s! Z. Gtvb now,tvbnow,bttvbfrom the heavier six, split it to three on each side
* r$ E' V/ O# g" z: ~; u d6 b) ^/ {- L4 Q1 R1 Z
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |