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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
3 \2 y# Y$ ?/ z5.39.217.77共四堆
! o# f1 C  N& V/ Gtvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重公仔箱論壇1 E$ d6 l& G) I1 P$ f
在异常的那一堆中在称一次
5 m* t& ?( ~1 K8 q( J& ~( _) R就可以找到了
divde the 12 balls into 3 sets of 4. 4 J' a5 V/ ?( f' A! }  G
weight any 2 sets.
. H* d8 g" |: M3 b( ^5.39.217.77if the 2 sets are equal, then you know the heavy one is in the third
  }; P" p: g( B4 L3 Q8 z& x( VTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if one of the 2 is heavier, then the heavy one is in that set
+ w* @& S. D0 H公仔箱論壇then divide the 4 balls into 2.公仔箱論壇- C" @/ h8 A' _; W; |) k( W( x
weigh them
+ N/ j3 M! N4 b2 C6 }$ M/ I. W6 }- w7 N# KTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。and divide the heavier into 1
% U, t, T: j, B6 R4 {8 ZTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。and weight them.公仔箱論壇0 f8 }8 f( y. E7 ~2 Q6 P0 U
3 x weighing and get the ans.  
9 j  \9 m# {9 j, ]公仔箱論壇in less than 15 secs.
1. 6 aside and weight.5 I/ u. o8 ^/ m- [0 ~8 V4 W$ v  T
2. heavier side from (1), 3 aside weight again.公仔箱論壇3 i. n2 y5 F1 i6 y
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
( Y3 E5 d/ ]  Q5 {# T! R4 H( n' Ttvb now,tvbnow,bttvb公仔箱論壇% j2 o! z) L  l& N
but i have a question. 重量異常 can be heavier or lighter.... so......
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