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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
: {8 ~% F" v, ?6 U8 x共四堆
0 r9 {/ k' X% B3 [5 S4 E) j8 s) S0 z称两次得出异常的在那一堆,其轻重TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。7 u8 l9 W( n, Y& ]& j5 `$ U
在异常的那一堆中在称一次
: p% i  V( i( l. Z5 ?7 M4 |4 @1 k就可以找到了
divde the 12 balls into 3 sets of 4.
5 L' s. C& b) b# N8 W3 W+ K/ Cweight any 2 sets.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- d  m  Y! t+ w+ F/ h) q3 t) e
if the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇3 ~; F# |& O; u- Y; N9 a
if one of the 2 is heavier, then the heavy one is in that set5.39.217.77* o  J/ T% K' C) D
then divide the 4 balls into 2.
3 [! Y, y. b, M9 @+ D6 oweigh them/ h% d; c" j. E' g6 `
and divide the heavier into 1, C2 P9 Y+ r: p5 K( @0 _6 x
and weight them.. R$ n3 h% T' Q3 M6 q( ^. G6 X- Y
3 x weighing and get the ans.  5.39.217.775 y% W5 X5 g. X
in less than 15 secs.
1. 6 aside and weight.
, c5 \& Y" J% N1 ktvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.tvb now,tvbnow,bttvb) c/ V1 c0 p! x" e) @
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. tvb now,tvbnow,bttvb0 `3 C2 E. U& P5 [/ b7 {# f7 B3 w. Q

# B6 O8 G7 r& A. ~公仔箱論壇but i have a question. 重量異常 can be heavier or lighter.... so......
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