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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
+ b: @7 H) q: w9 i7 }7 @5 f2 U共四堆+ A7 f9 N) L  A
称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb' g! D6 `( t0 E6 r+ c
在异常的那一堆中在称一次
1 `, N3 b0 L/ i- Y9 e* ~* v( |tvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4. 公仔箱論壇# [) u* U3 I! L  g
weight any 2 sets.
7 S& y) @2 L: `6 J3 k$ hif the 2 sets are equal, then you know the heavy one is in the third: R7 g4 Y  y; r" }
if one of the 2 is heavier, then the heavy one is in that setTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2 u  M0 J! h+ ~
then divide the 4 balls into 2.tvb now,tvbnow,bttvb2 e3 y) ^$ V7 v. o) Q' ]  w+ Q
weigh them: H% [' Y  l) }+ u# V
and divide the heavier into 1/ O  }9 Z  H; Q6 J
and weight them.
0 ]8 f+ H9 _% q5.39.217.773 x weighing and get the ans.  
: w' Q& F' t( I2 F1 C( ZTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight.
2 i0 {3 ^' i0 s, Jtvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.
3 m9 G; e8 U: ^  ~% h1 D8 S7 Ttvb now,tvbnow,bttvb3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.77: h3 n1 Y2 M. D7 t/ q( q  V+ q
公仔箱論壇% U' Q# m! A7 c
but i have a question. 重量異常 can be heavier or lighter.... so......
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