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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆; Q  u0 v7 Z9 O* s
共四堆公仔箱論壇6 G: z, ?4 b5 Y6 L/ N7 {
称两次得出异常的在那一堆,其轻重
2 y4 d# {* L4 H# Q; b( V; HTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。在异常的那一堆中在称一次
# E, s! Q+ Y9 L/ C& i就可以找到了
divde the 12 balls into 3 sets of 4.
3 r9 \: N  G9 [* u; V% s& \tvb now,tvbnow,bttvbweight any 2 sets.
8 @% j+ x/ ?; `. Bif the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇. T. S8 o- }3 Q1 d7 E
if one of the 2 is heavier, then the heavy one is in that set
" G: r! O8 O. ]0 Y$ X5.39.217.77then divide the 4 balls into 2.
4 @- Z! B) j+ k% Q. b5.39.217.77weigh them
, S0 W, w" A' `3 |  @+ w5 E+ Aand divide the heavier into 1
" H0 p4 g$ L6 S( I" g2 q3 q公仔箱論壇and weight them.
3 I; [6 _0 \3 a0 ^' b0 E7 x4 x9 V3 x weighing and get the ans.  5.39.217.77, a" i' W% }4 y7 [- q& P7 Y8 I+ V
in less than 15 secs.
1. 6 aside and weight.
1 O! _+ ^4 {9 {8 Y/ i( p! Y: Y6 z5.39.217.772. heavier side from (1), 3 aside weight again.
$ G, Q6 x' x$ o- F3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
; O2 \( r$ W. h* x3 `/ Z1 G0 s5.39.217.77
% c! Y8 e4 |% L. ~. n* Q- fbut i have a question. 重量異常 can be heavier or lighter.... so......
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