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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆7 x7 _. b1 ~0 I! K# ~6 W7 m
共四堆
- L$ B' o/ ?" ?1 ]# g, A$ w5.39.217.77称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb' n$ T. k- c: D7 Y8 p" G* G% h2 g
在异常的那一堆中在称一次6 }7 U+ T/ l2 H6 D
就可以找到了
divde the 12 balls into 3 sets of 4. - \9 F, ~9 y1 S! f  W7 q$ c
weight any 2 sets.
% p/ m3 s, v+ H$ G; J6 a: |( ztvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third
7 B5 ~1 J/ r, ~. ttvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that set
9 C2 M0 X4 O* otvb now,tvbnow,bttvbthen divide the 4 balls into 2.5.39.217.77: L: y( A8 z8 u/ f  T, B) O0 b
weigh them5.39.217.775 s' p2 ^9 o: v: R
and divide the heavier into 1
+ c+ @' |" ^& U2 }3 d1 `6 e5.39.217.77and weight them.
8 D: v4 W* d$ wTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 x weighing and get the ans.  9 [/ w* V% Y# k1 |' s/ W
in less than 15 secs.
1. 6 aside and weight.
5 S& P6 a( O7 X5 g1 g. STVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2. heavier side from (1), 3 aside weight again.tvb now,tvbnow,bttvb& x7 m" C9 `2 E  G9 o# d
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. * t* V9 U1 k3 J6 }
tvb now,tvbnow,bttvb7 ]7 j  r7 \& Y+ S: z% a+ Q
but i have a question. 重量異常 can be heavier or lighter.... so......
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