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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
$ \2 A4 b& r( |( K6 S( H( U公仔箱論壇共四堆  a& l4 @% B- X9 }% k- c2 @
称两次得出异常的在那一堆,其轻重
: W6 J4 t2 z. f* b* ]在异常的那一堆中在称一次公仔箱論壇7 W$ p& H: v: a' l3 R$ z! r
就可以找到了
divde the 12 balls into 3 sets of 4. 6 {( l. P' V* t4 |
weight any 2 sets.tvb now,tvbnow,bttvb0 P! p) b" A+ z/ [
if the 2 sets are equal, then you know the heavy one is in the third) S7 F# `: F; v- C+ w
if one of the 2 is heavier, then the heavy one is in that set
8 W( s" i: ]/ c& h9 U0 U4 r公仔箱論壇then divide the 4 balls into 2.
# ^0 a+ C7 _3 F7 _+ |TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weigh themtvb now,tvbnow,bttvb2 `3 J. }: k$ H/ z; h! j
and divide the heavier into 1' j& k7 C: B+ p8 E
and weight them.5.39.217.77) ~9 ^( K) }. `; d
3 x weighing and get the ans.  4 z7 y$ t* |+ x% o  z& n( [
in less than 15 secs.
1. 6 aside and weight.
5 w/ S+ ~8 g. n3 t+ bTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2. heavier side from (1), 3 aside weight again.  C5 B/ d' B! B5 W! z
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
& w. q% d2 U0 H7 s8 C$ Z8 g; q公仔箱論壇5 j7 a& s  }( M4 i0 P9 L  j
but i have a question. 重量異常 can be heavier or lighter.... so......
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