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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.77- I7 I; q# m- N! v
共四堆tvb now,tvbnow,bttvb0 U  A. o+ U1 `4 C
称两次得出异常的在那一堆,其轻重公仔箱論壇9 M2 `2 A3 t) c5 Z+ `4 k
在异常的那一堆中在称一次
1 }6 z5 v+ [8 C" Q3 S: OTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。就可以找到了
divde the 12 balls into 3 sets of 4. 5.39.217.775 i- ^* H* \/ S% H
weight any 2 sets.tvb now,tvbnow,bttvb" I& e; T4 g0 g; r5 T# j
if the 2 sets are equal, then you know the heavy one is in the third+ j! h4 ~3 P/ H
if one of the 2 is heavier, then the heavy one is in that set5 j$ v2 o: p( X. c
then divide the 4 balls into 2.5.39.217.77( Q1 s$ m: P( m
weigh themtvb now,tvbnow,bttvb, D* Y" }6 T; e; Z
and divide the heavier into 10 S+ y& h; B0 \
and weight them.
  d0 S& L. X; gTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 x weighing and get the ans.  
8 ^5 t( b" \, B& Z1 q5 d5.39.217.77in less than 15 secs.
1. 6 aside and weight.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。. n* `+ ?2 |. P) ^- {  z! c- ~: q# t3 E
2. heavier side from (1), 3 aside weight again.
' Y& w& F$ L, B' v$ y4 [1 @% P1 ]6 iTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.77+ {+ c2 ]$ ]% X" [

# Z) j4 v, h7 g" ]tvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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