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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
5 }: r. ^5 q6 d( j+ LTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。共四堆5.39.217.77' `$ G" p# C) }/ S- [3 c9 o9 g
称两次得出异常的在那一堆,其轻重
0 \5 ]; J' l4 o. ~公仔箱論壇在异常的那一堆中在称一次
! }. P0 q+ T9 `4 S& p就可以找到了
divde the 12 balls into 3 sets of 4.
1 \9 r% y; [3 k' c7 [weight any 2 sets.tvb now,tvbnow,bttvb2 y* D+ ~, I2 Z6 p* l) |
if the 2 sets are equal, then you know the heavy one is in the third+ Y% ^2 t& e) g* S6 F
if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇4 B8 A5 H$ Z4 @3 O# p
then divide the 4 balls into 2.0 w9 c' Z9 i2 t4 H# R' Q: G$ n6 e6 T0 O
weigh them
4 z, s& R: C8 ]+ j; w+ D/ C; ?and divide the heavier into 14 x+ R" i" r) |" g0 F6 r: @0 d
and weight them.公仔箱論壇+ ~# f5 v/ {7 k* s; R* w- I
3 x weighing and get the ans.  公仔箱論壇0 v* ^. B5 Q  q2 f4 H
in less than 15 secs.
1. 6 aside and weight.3 w- N! V( G1 \, K
2. heavier side from (1), 3 aside weight again.# O( C0 U( b, Z* a* R! v
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
* ^, p4 L; z3 L( c, A3 Y5.39.217.77$ D( }1 u  F, R1 n2 F* {
but i have a question. 重量異常 can be heavier or lighter.... so......
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