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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
7 E/ r3 T4 p" M+ u- u  dtvb now,tvbnow,bttvb共四堆
. f$ ?4 \5 P0 t2 p4 i+ q. Y  y- k称两次得出异常的在那一堆,其轻重5.39.217.77# \' s0 J$ Q4 ^$ {; k' m
在异常的那一堆中在称一次
0 f/ Y  `) n& l0 U% Y+ N1 G5.39.217.77就可以找到了
divde the 12 balls into 3 sets of 4. 9 ]4 v+ J" ?/ E  B
weight any 2 sets.  s) |8 S$ i1 x- }& E7 g
if the 2 sets are equal, then you know the heavy one is in the thirdTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。! j. N. i2 Z1 K2 Q# C
if one of the 2 is heavier, then the heavy one is in that set: g3 M# k, j, D3 Y: H+ S
then divide the 4 balls into 2.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: C* \' p( a5 q7 H
weigh them
0 ]% w  w+ e6 n, ?tvb now,tvbnow,bttvband divide the heavier into 15 ~! F5 z0 x3 |/ S
and weight them.
9 R! Q* ]' N3 u1 h" V公仔箱論壇3 x weighing and get the ans.  2 L& u6 f5 d9 T
in less than 15 secs.
1. 6 aside and weight.
1 d5 M: X6 m7 |  J1 m2 k, Btvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.
( u4 {0 m; F' d# n2 f4 d. Ftvb now,tvbnow,bttvb3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 3 m2 z5 i. T  i" g
公仔箱論壇6 F: D. t  G% ]
but i have a question. 重量異常 can be heavier or lighter.... so......
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