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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
1 j0 x5 Z8 k/ \3 g6 {6 f共四堆
( c; x: J( x0 U! w- c) ^称两次得出异常的在那一堆,其轻重
/ G. Q8 c& J, q$ a4 i+ o在异常的那一堆中在称一次
/ R+ E8 r$ Z: s" B9 F/ [1 xTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。就可以找到了
divde the 12 balls into 3 sets of 4.
0 W+ m. j3 a8 w4 R4 q$ Vtvb now,tvbnow,bttvbweight any 2 sets.
# B  i. J: N& N: o0 p: W0 r5.39.217.77if the 2 sets are equal, then you know the heavy one is in the third
. w" Z9 u4 |, Fif one of the 2 is heavier, then the heavy one is in that set5.39.217.778 Q  f  u6 j' p' c4 h; G  g; x
then divide the 4 balls into 2.
5 [. I8 D  }1 M: B4 Ztvb now,tvbnow,bttvbweigh them' q  x1 [  g+ G
and divide the heavier into 16 [9 {$ i' p2 s1 u$ w
and weight them.公仔箱論壇8 x0 i& o: }, q" k# Y
3 x weighing and get the ans.  
- f1 B& R5 \- [( g. @' Wtvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.
- N8 ~* V3 X& _tvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。9 `( @) T: K, L
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。/ h2 B* U9 M1 r' L
tvb now,tvbnow,bttvb! c1 X8 d$ q; `
but i have a question. 重量異常 can be heavier or lighter.... so......
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